ROTATION OF RIGID BODIES
Linear inertia
Is the tendency of a body to resist change in its linear velocity.
In other words; objects do not change their state of linear motion unless acted upon by some not external force.
Rotational inertia
Is the tendency of a body to resist change in its angular velocity.
  • In other words, objects do not change their rotational motion unless acted upon by some not external torque.
  • It is also called moment of inertia.
CONCEPT OF MOMENT OF INERTIA
Moment of inertia of a body about an axis is a measure of the difficulty in starting, stopping or changing rotation of the body about that axis.
  • It is denoted by I
  • The greater the difficulty in starting or stopping , the greater is the moment of inertia of the body about that axis and vice-versa.
  • A body rotates under the action of a net external torque.
The Greater the moment of inertia of a body about an axis of rotation, the greater is the torque required to rotate or stop or change rotation of the body that axis and vice-versa.
MOMENT OF INERTIA OF A RIGID BODY
Consider a rigid body rotating about the axis yy-1 with an angular speed ω as shown in figure 1 below.
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Figure. 1
Suppose the body is made up of a large number (n) of small particles of masses m1,m2,m3
………..mn situated at perpendicular distances  XzWXEONRRLNJpzgYFDM XCbzxVIsLenlFC860CNY2DpHDYPwOKawcyAmPuBmiNdTymis4nJHj A1hKe9VKUxi4YituxGQbY4gtLtBpDaDZEbpK5rrPDOtcwAbe753mDTv6vaJo……………D1gyBD5x1C5VHO2m HUgqV6b5MwDc40V5Z4C6sEjKcjEqQeAr3trSnTRKzOvr6Sj7dXO3ueXJOklJX6YAWinAVEwlFH 00QJw2BGS3MXTBHxJMWNW6oDJDM4NOcpUcMyj59nA0k respectively from the axis of rotation yy’.
As the body rotates, each particle of the body follows a circular path around the axis.
Although each particle of the body has the same angular speed ω, the linear velocity (v) of each particle depends upon particles distance from the axis of rotation.
Thus particle of mass m1 follows a circular path of radius r1. The linear velocity of this particle is v1
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Rotational kinetic energy of the particles of mass m1
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The total kinetic energy Kr of the rotating body is the sum of the kinetic energies of all the particles of which the body is composed.
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Hence the total K.E of rotating body
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Moment of inertia of a rigid body about a given axis of rotation
Is the sum of the products of the masses of its particles and the squares of their respective perpendicular distance from the axis of rotation.
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The moment of inertia of a body about an axis of rotation is directly proportional to the total mass of the body.
The more massive the body, the more difficult will be to start its rotational motion or stop it from rotating.
For a given mass, the moment of inertia of a body depends upon the distribution of the mass from the axis of rotation. The larger the distance of the mass from the axis rotation the larger will be its moment of inertia.
The moment of inertia plays the same role in rotational motion as mass plays in translational motion.
RADIUS OF GYRATION
Radius of gyration Is the distance from the given axis of rotation at which if whole mass of the object were supposed to be concentrated the moment of inertia would be the same as with the actual distribution of mass.
The radius of gyration is denoted by the symbol K.
T The moment of inertia of a body of mass M and radius of gyration K is given by,
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For example, the moment of inertia of a thin rod of mass M and length L about an axis through its centre and perpendicular to its length is
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The radius of gyration is a measure of the distribution of mass of a body relative to a given axis of rotation.
A large radius of gyration means that, on the average, the mass is relatively far from the given axis of rotation.
The SI unit of radius of gyration is the metre (m)
Suppose a body consist of n particles each of mass m, then total mass of the body is M.
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Therefore radius of gyration is the root mean square distance of the various particles of the body from the axis of rotation.
EQUATIONS OR UNIFORMLY ACCELERATED ROTATIONAL MOTION
Consider a rigid body rotating about a given axis with uniform angular acceleration.
Let
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  1. To derive  Hh8P2cyzcaROF Y CvoseETar2nt G6Wpxikd68MaI7l F2nR8v3JiZYlLcZl7FsMXTVKAsybsMWrhl4fxNu09fcw QmM2r7CaSWxSTHt3 YeikM3hBU8gpWuWLTdKq0vBEoQ
From
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At JKkH6GTd5ZkH3chrvVSZZgpOQv1sT5Ru 57gVB49XCFrcLUwTLk08 R4XqXXo34tuweIwCIdhuHOgvO0mLE7lgEodCrikp8cL HDNRSlKeOrXiurWuC0e6Q4LdLzNpIIwS7pqLM
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For linear motion
v = u + at
  1. To derive 086qoxTwq6MEfyVHVUsR7tg DeMvr2qJLNcJUYTKXXyJlxwm0cbsizgS47Z4eyDGcZfikqmvOJMCPI0aZwBK1da VRCZrKsdPAH3t6AnMTDt98u2W J9UGrwQTQOlT4f5VEef5o
From R2I7gdpLeNBcRdTNW0aI4dhEIVNBpzf2zBMPp6nJDkcZe1oVF4xV4 J1VScDG0UISq7V4E9kgWR0HUqwixdf4FFxmw01YSPcVGFwokbR0nTafoTGNeP7fPaDwgYt7Ap4Se5HBtI
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At 7ufxsFfOSAz5OwQzDYrCrlFs8zaSR Rjv0JLneoApGl3aasv1gBdkvYAkvhIiPGtsg3b07TO3r1Xn9jfYW57tl4 FtaOBMwyutpt3CzRdN7wwwTHCBoQ63lu5Qsyf3jNlr35fRs
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For the linear motion
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Also MWu9K MOvvbs6ItzrCoE0SU Ahb Lb7061Xg4wQxRU1V3OQNAdqGb85ec3AtHeVVkZKH7yEmzBjd2A3DAgPdh9g4QA0bPdp2DcK6DO5q4zItN V8FnFGLUYqOWnb XBpgu4lq0Q
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When 0qbAihU9j6H ER1rPIkSn0VgDUCyo444Y3qzfjb9vpfFy233J ZBoaPvDDzmwvK IaB1Hm866Jw6dy2xlagNVCFn5ssiSochBG5ZQ5J0SWVHhfTsWT5PTC5ZvmjXDoK4KRAvHbs
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For linear motion
v2 = u2 + 2as
MOTION OF A RIGID BODY AND MOMENT OF INERTIA
Consider a rigid body rotating about the axis IKkuyY NbhcLo0V37rJMMLG7VMv55s7yc76F P MS4xtgVutazsG1bE87ydS8xy5qHP8a47ufBFpvWhvpG GFNDyHlR9e6SOFd5rHiBYHRRvVs1kZi7x1pTIuG1OsQB5mKhCgfUwith an angular speed 2D27LQI3un6D2gaIc465iGhMiMszauN5kMhzSESJyxBH1zqL14y1Po2 Oo Fg1XPz08QHZAvQmfjw5QKzGIPWxdCTh7jsL G0oU4Mr669NqQUdPNZXn2HTSJXOIiZxGao4nxiYk as shown in figure.2 below
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Figure. 2
Suppose the body is made up of a large number of particles of masses m1, m2,m3 situated at perpendicular distances  XzWXEONRRLNJpzgYFDM XCbzxVIsLenlFC860CNY2DpHDYPwOKawcyAmPuBmiNdTymis4nJHj A1hKe9VKUxi4YituxGQbY4gtLtBpDaDZEbpK5rrPDOtcwAbe753mDTv6vaJo……… respectively from the axis of rotation.
As the body rotates, each particle within the body follows a circular path around the axis.
Although each particle within the body has the same angular speed 2D27LQI3un6D2gaIc465iGhMiMszauN5kMhzSESJyxBH1zqL14y1Po2 Oo Fg1XPz08QHZAvQmfjw5QKzGIPWxdCTh7jsL G0oU4Mr669NqQUdPNZXn2HTSJXOIiZxGao4nxiYk, the velocity of each particle depends upon particles position with respect to axis of rotation.
1. Relation between rotational kinetic energy and moment of inertia.
When a rigid body rotates about an axis, possesses K.E called the kinetic energy of a rotating body, and its rotational kinetic energy denoted by (KW5lOlkGklHbWM60KQNWO3TA0HLkVALCy9aEWem3 5 Mdjy6 Q42B0mEYmtLEzFxyznhYkQgm986hziZ0xypYuGFrIlmUoXPZNnopqD6h0W0BUA2jjGM39CAeT0KsrBT9S3y8vQ).
Let us now find the K.E of a rotating body. The particle of mass m1 follows a circular path of radius Es Ua3vSZ9av5I9vAAhgoNxLP93WMEQDMICeiw04EpGzMVyjWYHZ1YHv6JesdqS1aGRzPl FcJf0ULc42rih QYqjrEzX3huOsnhjFElS5jbykoGrklvoRqP1AleWh2qhOw FaI.
The magnitude of the linear or tangential velocity of the particle on this circle is v1
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Similarly, the rotation kinetic energy of particles of masses
The rotational kinetic energy of the body is equal to the sum of rotational kinetic energies of all particles Image?w=461&h=66&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
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is the moment of inertia of the body about the given axis of rotation Image?w=265&h=132&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
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Thus the rotational K.E of a body is equal to half of the product of the moment of inertia of the body and the square of the angular velocity of the bo
dy about a given axis of rotation.
We also know that kinetic energy K of a body for linear motion is,
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  1. Note that both expressions for K.E are one half the products of property of body and square of velocity term.
We know that linear velocity v is an analogue of angular velocity ω in rotational motion
Therefore, mass (m) of the body is an analogue of moment of inertia I of the body in rotation motion.
Hence we arrive at a very important conclusion that moment of inertia plays the same role in rotational as the mass (m) plays in linear motion.
  1. If XrLWuihWZPWeInECBdTBH2JK6vmUy73nfXw0uI1kVe9H JnEGQl0KWgNSChOAa0f1RD7unXOo77ukIbx6oXoK39dTWfVYw8gd3Xc93uZs73PlH8xwlPfyb 5AHAV 6MgXosdSy8
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Thus, the moment of inertia of a rigid body about a given axis of rotation is numerically equal to twice the rotational K.E of the body when rotating with unit angular velocity about that axis.
2. Relation between torque and moment of inertia
Suppose a body rotates about an axis under the action of a constant to torque τ .
Let the constant angular acceleration produced by the body be 4r AQb0ihCuB5I3Td UmheFeLpMljvOZrdzGg2q S7a8x8W4ko8z5bFiEpvEGamzudke88MF9gxIPZ NAtifkwekTEgt8GDXn3hMx3VWRX1tNGmWK 5MKhXc9 MTB YMzlxT3dw.
The angular acceleration (WDZsLnZxwzrkdkaojS5sYLYPmEuumckUV0CeVHDwhMy85nNtDE94DMeqHXVVkwN 0K9yWMfmLrbTzIFfJ58uyooMWY8iPe2eZQjcSSXIfz2rLM2PPx3Mgsa4VE4HZMF1o9ML1FY) of all the particles of the body will be the same but the linear acceleration (a) of each particle will depend upon the particles position with respect to the axis of rotation.
The particle of mass m1 follows a circular path of radius r1. The magnitude of the linear acceleration of this particle a1 = r1 PpyfSM2jLFrXncehXSdduaN8XTTEICHSt9ikSGKGyIDEMmhEDPya0Q3 MTKJGnmmlgBP3ylgBll INebuw0owazCejrN9TzN9sSLy YQP OXFXjdTXpS0OlJ5wv2Kg 0 G6Jt68 .
If F1 is the net external force acting on this particle
LzQV8C UCPZl2HvTkr6dCXHg389VsjVTPyd0RbEtZ55Wvht69lU6HxsL3o3el2Gs8eZJs4bN8lqUTDzNPgh1P5ASX 5PQfrFpy0LkDSxwbE63xKblzrdJA8Amwfp2RdrAvaEnoo
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G3 EdmY1dhgvwLl13NOcWiD8PZqMX GM2dzyChLyRYARsJ47e5nTYStCHujFFc5kdjW FmmwKUuXBJY2e5molvNe0U3MFA3wbtDzLE8Qebew94 F4PG0e90MiTN34jOMyC8LCL4
The magnitude of torque due to this force on this particle
VNBJTfglX3ZsuV0k4RmqnqVfqXaYVsxCLIZG2B9pazGxT1SPtqfYpLgDuIBI0NKSxsez2dXHsmMO 8KJNRRF6kbUriatjE5XZ3bv6z2fjnXchmxWpdct2WTtIRcM02 Ujbz0k W
Similarly the magnitude of torque on the particles of masses m2,m3 ….. … .. are m2r22PYmFh 4eTOII6YuEiYasN6zxlNDNV56HoDNqwa69IlQnvTqpgGI6Aq0SY7lEhyyRzTtv6DDYzOI4nk7CSp F8vn0cxbqokHDutNa9t5hcz2NCw0FyY7PgLzdLGJE690 8c9yWMU, m3 r324r AQb0ihCuB5I3Td UmheFeLpMljvOZrdzGg2q S7a8x8W4ko8z5bFiEpvEGamzudke88MF9gxIPZ NAtifkwekTEgt8GDXn3hMx3VWRX1tNGmWK 5MKhXc9 MTB YMzlxT3dw………… respectively.
By right hand rule, the torques on all the particles act in the same direction.
The magnitude of the total torque QWwJzVcs9pmrexhZ5qG17eTZ NPgWSuBsiRdRXNZGPEswiafcrD3UE3fsQ EEgXzCCSA3dswALQQ9ZO5A8xydaP29uhVVMnCWlkEkOUo70 Nl1ReRNpQ KeYGCZxI1UiFBrfw38on the body is just the sum of individual torques on the particles.
WryJVsilVCSoUjM LdNY6legtsXPi39zuZWZRgZ43KFdh33WTruNWA5pvgergZu8ECXsNqH4kPYIwqKJTNOs341ikF Rx8CzTsZeguK75a 3dkTIDsbrjB7eV9P3hqSSOWuftZM
E0 DhRushWmA7ChtRmLa1uaJXu1ZHIj55Qt D2mbY3RNi 3BugqN6XHk B7LuPgmlHkrD1NoA9OgHiiqSFlnRnstChh 4CWhLHkx OtvmtppPMz MqkHiRoXmCjxgaStRBom5kU
HAFLF UDraMIdwQqAAut6TC11JBgNL7QV88J2lK2IyGR 7tD6HddBCYvR7SL9LwR13LGt8R4u IcFn7yQvTv6jm4wLx8ZlWSdx6iWBJtGnsjmsklSOxqMNHBhH7 U 8kAW44Ns8
VM8F3e8liX AcIcGxp9RI1mEnSYyqn5BbZmBCm5XxqV3zjlvrDa5hEkTNYHUNNIIwM7eDY1I9y8nPZZpC9mQRH2fakiBJQHsthQR4i7tI48A8kKP2e 9NL1CvNq6 7YF49ubEb8
But FCvNqQ2K3yUJ7DcDRn4UVqCFyAZPno E BLmMhmua T8oJrUr9RyTzB4Rr33emsOcGV1LMDS5KDWcGZcjCKquk08hqkuivqTy7UlIf GlbFqikqS KPvrvI88uwaKX0w9QPcKMg is the moment of inertia of the body about the axis of rotation
RykvFp8J7 FEnAqZsOv4ymMEWCM7rE9Ws6ceRx1WP3mUxE1Uaqpuro6pqs1mnqAQRyz1q7 0D2xMcThLgDYULGMiSYsO4Mb6 HANcBIDI 4cKAkszfLgwGoZatEK JF43kNWPGE
 This is basic relation for rotational motion
RykvFp8J7 FEnAqZsOv4ymMEWCM7rE9Ws6ceRx1WP3mUxE1Uaqpuro6pqs1mnqAQRyz1q7 0D2xMcThLgDYULGMiSYsO4Mb6 HANcBIDI 4cKAkszfLgwGoZatEK JF43kNWPGE
It is analogous to Newton’s second law of linear motion
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The torque is analogous to force F, the moment of inertia I is analogous to mass m and the angular acceleration YDpvpZZ0b8rGJe NMMhPnma6bOVMsSMZAo 1MR9d00isggr8HvxbkiMZt26IwlEJLj6dVQf4j Mks8MWFXS0Ad4rLfHngZ6 RAaCioMr4MiRluyDZLipQvFR3La XWD4 P6xAc is analogous to the linear acceleration
If WEkBZgiSzrQaTkGqHZ EcXf7bwbC Qf5RqekNW28Cq2o9yrBLVJ6a2K98Tuse1TtGImAfvvM4FfnJZLUnrsOVBftB T69Nmle6Nj7uRJONSasXPpaZX9dSxnVn4r84lsDUUFN U
RykvFp8J7 FEnAqZsOv4ymMEWCM7rE9Ws6ceRx1WP3mUxE1Uaqpuro6pqs1mnqAQRyz1q7 0D2xMcThLgDYULGMiSYsO4Mb6 HANcBIDI 4cKAkszfLgwGoZatEK JF43kNWPGE
8uu 9gk2NtgRTLc7svbuC0uJVnYWrlrbTeUy132 VojM7VKw7g7nyW9e7qOvlLCDqhbjSSao33kXxR0ONH9Vp2eES4iFcCDYHISJUEKoCk0y9wntv3 PFVLWdsTF0RiMKifmr5k
Hence the moment of inertia of a body about a given axis is equal to the torque required to produce unit angular acceleration in the body about that axis.
3. Relation between angular momentum and moment of inertia
The particle of mass m1 follows a circular path of radius KnHgLG47gl 7qShJatSEYN8eI3I2iUBtxMmL 4KZbHQilPKQg2P MIcdb3JaAAcXAMFCEZjQhFUwHhdgUxD8Z7lNUfBjFJRYj7MsHF DtG9JCiEng F1lJXYPJkzXiw0Fp8yHQw about the axis of rotation.
Therefore, the magnitude v1 of linear velocity of this particle is
SfYg18SkZuZqG9xRkxga7zT78qQQOjA4yt4KoX9jmZWv3FrUnjYU0IycnEjNGrnBScJAdEAzym5rLNDhPEsCoJ4FRXLTT2qSJg9fVjIzJxY8P06BhDWWh7xc2gE 1SVkIxBm45E
The magnitude of the angular momentum of this particle about the axis of rotation
= linear momentum x radius r1
= m1 v1 x r1
Similarly, the magnitude of angular momentum of particles of masses m2,m3 ….. … ..
are m2r22ω, m3r32 ω …………….. respectively.
By right hand rule, the angular momentum of all the particles L of the rigid body point in the same direction, parallel to the angular velocity vector.
Therefore, the magnitude of total angular momentum L of the body about the axis of rotation is just the sum of individual momentum of the particles.
L = m1r12ω + m2r22ω + m31r32ω + …..
= (m1r12 + m2r22 + m3r32
FZTy4JtxC2 F7a8nplZju8j8yS2nbX61ExS2MLjpLANLV5Vyn6vUxOMFwvJUsOgnyQC FyA9iIAqBJ9EcMkzFjtdCE1PNAZoKIyVOKuETbv ZnusD1OY4oasMKJ PVVaEi ZI9Q
But SXwk85OH2CZTWQy1gxHQ4ueTeKBqjN8zo09yyF1fX8mfza 08jaqK3jiPXCJLgUN3UTIgargNlzBjPinaGeBE1svosqpxDDQ5iWpb TR2 IwDeFDbN0rx4XbGeF7fenowAOLDFc is the moment of the body about the axis of rotation
DVMutaQCTkquF3zDj3E8gFoZMJzFicMBkJPXOIsjzvrclHYLUevevFuFSGqEK93lbo6WQF77ClZQd3jLoSe1I2rKFRwOVSolF M99tJog Y XqXSH3U ZR5JcGi1OoE29zE4tdg
The SI units of L is kgm2s-1
4. Relation between torque and angular momentum.
The magnitude of angular momentum of a body about an axis is
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Differentiating both sides with respect to t we get
QiQzMftQsCakwLJIQuOCI1q4UKeUYEpdYdPVzdLDBGxHccs64zmvDXvV H6a82Oh16CUqk PYgdKP3ak5jtxQih6 Z46I1L48MOUCTetzH8rXPI5gUOXc9 QvVwvtThcfOLRdiY
FcNVOZeILO0Prf5 GsrZDwvKK7saxIOhJjhAp1g6Z0XCLXRvQXYH9IR3WpNotYG4h8xVPuy3AvtLgFtFvNQmOcaFb8FDnVk7 YJ0fb9Om3eePZXX4swLp6U3 12E1z9DHEfW3HQ
AvHrFTJnNuynpURhcK4mZtGswTZqZ 8Q1bSacvmYfOP82a7TuzRLQMA14yinxgFSqXyhEm1TQNmZa JMh35YpyHheNnlQ34kte2URgAQ AXCoddAOAyGt1MZr2I2wEgODxPGkZY
But Torque RykvFp8J7 FEnAqZsOv4ymMEWCM7rE9Ws6ceRx1WP3mUxE1Uaqpuro6pqs1mnqAQRyz1q7 0D2xMcThLgDYULGMiSYsO4Mb6 HANcBIDI 4cKAkszfLgwGoZatEK JF43kNWPGE
Then
TBCTJvtlm4zMVJhveqWcoAggkapKsZ7RDm 66YRp3c23v8VmlZ35iDr44xaCnXKiGifjG3AKEMZ4VggJKGAjzHlZF0 D03xurqKWiNGLSXrscWJeoKmqEeUiB6Vt ULnlB2aV O
Thus the torque acting on a body is equal to time rate of change of angular momentum of the body.
Power in Rotational Motion
Consider a rigid body rotating about an axis due to a constant applied UbkuGuuYBQPlnh5nCBZBta9kzz7Hkb7X1wJkholsrH5THfpo63C PlPzyHbMtiFmiSo OjptMre3UQ8qROWT76Dt9gnwtobP0qnUGzyl437 BTslc9rP4dMnCUtuLZlzgOhn1 U.
If the body rotates through a small change angle YTdyLUGc9PcdeiBMqHHgFUoC8EIEbWh47qn674ssEtLetJwkUVgwuTENYNg91albJ5btLfaNaAQz3PPCxxKEh5Cz7 Fr95NE6u8vxCO6u5gnvrTDRGWRDVI OFCS09Y3WXtlceU in small time 3oH7QDImRR6uopTvSJtUKbJvK9e FsDNgkOMIu0caKPvotAt0SVQAKlif7B84GX5QY0Mr3WCXyQMW KwPGGZjjT0LoS4sq 12XnVRzP66YEfbEytjZKqL77elWQMHnTp9qBN UYthen small work THuKmZZvqgTudf4vhZPC KZgrdrdnHQf1N5LVg7zB QHHI HzpDpT6TQJfJI1evpjqjRdTzZRrs7iNqevKGiEpGgcGATm2z9QPEEsP0nnVglwTS6sNB 4UOxcrtu4dnef9zK0FQdone on the body is
ZbhLj1uke32kg8l2 Lx0sddcTaJ952JTMkMhZfRu4dqrP1KKJgGFsIiWajrjkI9Nbyivm4jxPqLFXG3C3wYrjWLwyx95cthpdFJyTKZiJ0Bo248H3uR1Ur Nqn5SAm82putXm8k
BENCU70 EYrLguUNZn1jpPy8y5ISxXbzFBRdqgsF3eDz29UYm V8k1gkvoJ8mO3o61MsE5dJvKV NFQZOrCtMtcuhS6h W0vhMIPIDMZS1MTb M9Y2A3J1q05ZdgrhLtgfgAsc
0fKlpv XSQoS A0m70p0yE2PYFwpP14X8cR2o0dp6Pnojh98 RlEQ6Kjd7luAKCy38jqfd U7 Rj4cE6WgyAdCeh0l82o9l7iODEfNwwKEjoDy RhmlWCBFpvChflyhN6kUmv6g
ESzbgICQJ6YDBC3x7zY4Sac8Rbl2YAQ64K1siwJZbRBhIZp Rr29an03uRYd02ZKYFnMMTbdW4T3vuaQqKlnpPbIqCyY0PRI1Cl Cj8EKpDKhf8Sxme2EiRzExoBdw0LbbzA5ZM
Thus power of a rotating body is equal to the product of torque and angular velocity.
Work-energy theorem in rotational motion
In linear motion, the work-energy theorem states that the net work done on a body by the external force is equal to the change in body’s linear kinetic energy.
Similar, in rotational motion, the work done by a torque in rotating the body about an axis is equal to the change in body‘s rotation kinetic energy.
Therefore, work-energy theorem in rotational motion may be stated as under “The net work-done by the external torque in rotating a rigid body about an axis is equal to the change in body’s rotational K.E”.
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LAW OF CONSERVATION OF ANGULAR MOMENTUM
If not net external torque acts on a body or system, its angular momentum remains constant in magnitude and direction.
JUNHFc7yjG6bJSrDv8wFls7rD5Q6sSSrElRZkYq0w8Dne9GgrbghFrHA0f1UGx8lwK2V8DgeGx5 M1pCsNfmFPame4ZBA5BnTxSVYI1mLpVJWCyGmhL1wBFOQmQqQUNSeNoqW20
It is very important to keep in mind that it is  AEqps LOQ49SFOZX4PC2zn1fjjYYanOw ZW02pt38nRiwuI JaFIce1esDKOStrTCNBMcK1 ETG6ZAEgGDpgUix1oj5z3ed6H2OW7aybEmzgtu5cj8id8zSCfTKAo3wFCb5Wl4 – the product of moment of inertia and angular velocity that remains constant and not the angular velocity ω.
5NaIrJs8Y7n65zIyQsDrYxOChiK M93PmUSJUYo Uanb3giZHCENZ DL0ZRTJ3fYQNXgQCDta4ptR0amDB9EqkrAwvZo4ZYhDXVJoccmziecVI2u9jMnSolWTjT9LLsBXFniPqU
MOMENT OF INERTIA AND RADIUS OF GYRATION OF DIFFERENT BODIES WITH REGULAR GEOMETRIC SHAPES
1. Moment of inertia of a uniform rod
(a) About an axis through its centre
Consider a uniform rod of total mass M and length L
Imagine, a small infinitesimally element of mass “JOLzGBfclkN Awy2JBVkMbMXfqLo7CSX J0wDFeuCShNLfrVRhRnFdlF5HiEAnHq3N IeQHXv6 5azuZ ETzgRPU SEX8YujWd KHTdACQG TRsk5UrAAJZy8hFzEzS9UVz SCc” and length “PH RTLmEL HexGMgguQd82jtsikJbqOLulkWYYtCk1U7LwDo29kZ Gpa5 EB6 ABS9l T31JdEQk9G1g6xX18D6WPUi3gcfpKZka3GAVGOc9kbFMpvF QPz9bduvEFzIILLmRMU” at a distance “7eUnwZeO9WxbZHKSuEPalJisKd Zj6y1XVnalPrSX5XcbBthqkQow0O24paiQ6EVSOZ981OL KRrG6Umr RqEOI3sf1ZfHHi4H3EEvDT SKEivi9vl GpIkcH0jv6R1mZCQ9bQ” from the axis of rotation passing through the middle of the uniform rod.
Tb9ZxylcCwE5PEmJWRFa7FNaRCvQeMiMBNpS8UqzguphS4lv9e3jCoITUXiPMWyhCzeSD7GrjYhG4VyIXKpnJGVCnh2 DQ51Y4G5f7V Bjph CuJzlrxRhOMJVgSw6Mykiw Ce4
Figure. 3
By similarity
ZOM1t Yyh0DPhDOt9v8Gs LgmgskcafUMEhDxdVssnHKCd1QnStlI5wl8alJDEqBnwawup0qxEDFmkkS905pJ0KXz8iRvuD08uRtcPKPeRweQLM2y8vrSZlheJkpLJgwvL8hSQ
MLF8Gw Ozth3g Q01M BaOAU3AfcgI9MOX A8sqQywCsjHzgsTABJu25DNcgb4VkbVgh4ZslJ312bxNNqULXfWnEcQiVGrD3HUtEZB PlK8Rwygw8J3fI138KI1eI3Fb1X5mSPE
The moment of inertia of the imaginary small infinitesimally element a distance CKmYdDU8njqwxkkzMtj7GKD0nrbQ1ooVKmNw7maThPBlTIj4qL2tk6OJbuR5ZeucxlA2i6c5Gt5YoIOrcITJZSaMMQQklLxzXfGaiFzJ H9kTkIIHnHG5IfbZfAoOAmlwG53DQ4from the axis of rotation is given by
80cAfEvX75RCTnYxcQq8FcAk5C6tYR9VDFKMGQ70mrVkUghEQzOu 5btTxvczD2 EeqoZY68LHAfxwMviKst8xBgVd VmFlaOVRIUFNl2b5TW939SuWm5JNi6NHDUETzbXCeD8g
The total moment of inertia for the whole uniform rod is obtained by integrating the above expression
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Image?w=199&h=197&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
TrzOLLJQk9dDC3bh6jpUlEPeiZqF0BrlGLF6f3vYcifGmGXOJKz62n8YmR LByiTkF 8t M394g NrANh6eSIoLVFj6ichkJJHa4T9DtxiQtyxt1H4weZpH4 WWQQfGzHzaLC8
TKrBacgL4hBpr5sX53eLBBfh8CjdeJhwRDtOvakSTXTJq6r DUq PsoCnfmbzRWZcBsUCmVll6i9ZdZzWZ1vWz2KA S2j31eXuTuaUNIh7LS9 WO23qyfx9Jb1 P4tj3YPN38cw
IiMrRtMSGwo0OvC XDstZcZdo0 V25ZxWnFtScIK2Bv5k3GWSGVGSdr JoP05mCtgboRVakyHC24aH63bXYPK6WvCCCk7odHGmS5K KqMyG FX7lQ8kQ5PxDCRgTSC4qW4n IWk
Total moment of inertia for the whole rod is
Image?w=87&h=142&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Its Radius of gyration
6RafUyV I4086h2kpzkccnmPFVLpyhsAZzeMIuQh1Au70FxwebCZEslQFKXGEDATjrvBCCl33cTy1S 9v0kYgupbpuHV7FEpez4VKnA2ZKwKqLHUw3peYOIL9oG1LYzTpLJl2cA
But is the moment of inertia of a uniform rod about an axis through its centre
7Ov9N8fJjnq NhcrSp2ML883lEnZ80J9 TPf S2Ux CaqSSMgkvAnKJs6dMMTQLBbN2p 0ZyPTyab4kQhKQstgf9rJX2j93QqVvq Si4 50lcuQ71KcIAMCRoCYqpphD6ahhw84
Then
Image?w=84&h=213&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Image?w=94&h=78&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
(b) Moment of inertia about an axis at one end
LW52zyuj8jMfXib 5MfmXFCCyf Ovi EEfCc71PbdH7E7zInw1mHPe ZKA SPLIqyH4n4aGkQ5D4zSaJkdibvfh 37vHS4cM07k4TdpDxW6thLL7rCKZXTWVupflKyMAPEIs HE
Figure 4
By similarity
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Recall
dl = dmx2
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By integrating both sides
Image?w=131&h=209&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
 TRgrIJOOtLQJdjQTg LwMimsiauLqZ3Kckg3CqcS11RqPAvAQU X23Ianb8YH06t1iGkntRpC8Dht3 YjGo8gRxUXTC6snBkPXaefo3xRV7s8 A FpHBmGPf9bHUlRY7dyFyg
IQqxplughWwphoPz4C87zq4V7Hrbd6KXnSfJiayGS5Rfwv7afMUidWR1pnmRT8NEYTVGWbIAW03dBbRU3eo BHMF ZQUlVkb9Gmf5Uv2cRxUdpU0car9d09yqWjJfdqdjT2oPjA
  1. Moment of inertia of hollow Solid cylinder (ring)
Consider a hollow solid cylinder of uniform density is related about an axis passing through the center along the length L of the cylinder.
XfrNkCQiyD PP3q YaHgiFpZQ 3YF0g3aZ0aObVbPmdhXk0 B 08mLrLsBqqLsva C Ew3uruF903OOl2frrAG194lqGFraayS13Tg9OnhTcIt5pdBa1PQSgiCoIhCsYFVEZN9Q
Consider a small infinitesimal element (shell) at a distance r and having thickness, SnnmoRVtq2ql5i5YlXKGN9LxgmaogpPIZElQ88YHzGyZbhg8bMSDPBu7NPWDhBvEoccnhJFTtlZsagaTegrAv7UHfE WGdi8yJEX94pOV25r G7XLU7oWqF03wC0WGaGU5TOsws
then dV = area x thickness
MsYg8fD2W3ri1lHaTL Vxw3pm4O2REBOmX0D6DbJX5XfQy J DsAb6v9StABQ0Dz21 QbOXkIe4NZQZzDuVgbXBQmvNF GPfDa79zOcoGdCNSkcGegy8 SvGDjmknPPiY7P1EFE
CKEeIcL7GkuFVi81ndn NCFEtuyh3hRD3Fv7fnjOzVsETK PkDhR5x7GQlIxmVjVtpcJiKCyxQ7cH2AhPg8 BIgMg1AQK1FOMKrboXDI1N09nvQR6lxd7wgE1W9CZ516Fl CH 0
The mass of shell is given by
PT9AWluEcosPEcIjvnrfF Nz5M8FYtWpBVr1kel9G4W6tE K4KRG5D5Wt3ddaMLM8u5ItjwBiaR0Zus3jNHdsLI1Vuj GmGSvY0FQzI O7iZM10GX4Xs2npHK I 7irnsD9 Krw
9qlHoeWY2oKD WXcbMKAJ3ia 5KH4TMXqfQiJgKQMc5qPoXakF3kz3eWmyPMpb4YpNwbsKshpU9gBfJLRzv 6BpeGjV7qRgDjXjOgGDP7X66hpj1WTG IOXRu TKUZL8Iu1XAUQ
The moment of inertia for a shell
Gng1BvsoRHz79ZoLY55ZF0kZP8OjQsU1fN8eg3d2bj2q4FWyfjIgpBGWZMkZHMrHoexUob3RxjGOwJYBT6zEXE7nBzOgaUZCzwU6dqUocqKjcAIVsWUETGmdcJe6UgJgY7p3g6U
 V1cqAY MbtfoY3NwQky4WtiVHCvjFQacl6tXh Tjj6KFeKMF8BauCXTggrR6smYptvW5OcUzy1Fb5PaaYoxsdFt IiUnsZzWWhkN7S0a9JFJyzFElfRzNOZI6kFISSZJXCb TI
Image?w=113&h=81&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Image?w=220&h=447&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
But the mass of the cylinder is given
U2QPkCPx0PQB UFIlA02sFzjbjLsGhb1HOKi7ke4dfnF13I2z1w988 GjMyvm UrNwdJ AcCjh1Hkrpzh652LtBi8VOFThycP JfVZLzWH RmpNFIK4pnFtUeokIxWw0RXUdqYw
Then
N8y17 Oxi X4CFocQN 7P5bl MI XVsenSQL5tkX0k9AOZgFwqHbS3aJsxIKdZ2Tmq7zaDGYMmlMHCvF7BJrlvTv57zqXLT2x P3DMyimYoSUc FmM Ku5vP49xP00TPTTa9Nh8
Hence for hollow cylinder (ring) the moment of inertia is given by
N8y17 Oxi X4CFocQN 7P5bl MI XVsenSQL5tkX0k9AOZgFwqHbS3aJsxIKdZ2Tmq7zaDGYMmlMHCvF7BJrlvTv57zqXLT2x P3DMyimYoSUc FmM Ku5vP49xP00TPTTa9Nh8
But if the thickness of the cylinder is very small
Image?w=126&h=75&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Image?w=174&h=98&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
I = MR2 is the moment of inertia for thin hoop.
Its radius of gyration
From
F8bCP1I01r8v2rMkEAk0 ZmfAZQdf9tgL4yteArJphZaPv5hDn961o4gv2Ao3DWtf KU9cYpwfjrpIUMgcTs06cyajORA3A6Yjdlkk1ZzwsIuWhbTbxqLEux PJzULVOx 12ee4
MR2 = MK2
K2 = R2
Therefore, K = R
  1. Moment inertia of a solid cylinder (Disc)
McD86j1wUwSdQ9amyW76V7olY8LWkZw0oFzTnJgCGiRiNSL BJa2doFPOhL4ryn3FurG0 EsNZEdhRoFQ4puYdkAtsteoCbu6rWNS82pFMUjPAgeCUUifq2YcpyisclxJtNqhew
Figure. 6
Area at any radius ILL2vUfjuOeCfJRXVHJKKjuCR8 Ywvv28bTgB7sHp PiRq GCPiBLdoQvRXFKU2XxZrTyuAXpyoRhmwUSrT1XEtQRRW YaT GMx7jEIQEb5CAHmuAei4xZy HTc1Yb J6dgp52kfrom the centre of the circle
FmbS0LOK N43ZAnadqI61C2Bln3RE8SKyUX LlyDZF9bO SlZnaXEmi6W54GporwSkYlRlW9xjGwXKd76li5ppas3Rkf1XhZMAylOLXMS5FWeOdPLGj22iiaPFrMzs K41emXoY
Differentiate
JRZv6GcvBURs DKEY60x1Swk2qv7t8BN5 Io0tv4ajkgJ1tskqBuCGD22YiCfvLQ4BCgTZd C 1DHHHmpBpD82qiG8nCz5cqgNjBR1MLKM TkUJ JaxJYnmawTP1Cf PnuTh9qM
By similarity
WlZzh5dk 80CA8V O 22gOxuzKcn2Fah B 4oTx5uvWGNe7i0VLHT8Bg58cKCeE3o2xZqPR45AMrbe4XB4VlzDEiP51D5o3 JIvmpKW7D2gm0ev320MaNsl S7oBgxNQhIOhgs
G6K0Ux1XyoNd1W03rBXcXoN7 ZMMnKKdtWFRIyHDoQYB2cQhPJzlwbnt0y6A7hDCGnvpeM4GaesoN4qoEsGZwykd DuJBbmGNl7aBu51xzYyoJ1WEQKR 2bV8ZuZi974P TJU5s
DpDGpvvNR99Z6YZtMCZxayVg5ozn 4UmD ZGjHJnS9hIZongJde Q9zA1B9aDmLGaxG 8UVwx8wCwZBzJWfNORtl3GDSU6l Lhgn86 UpWk5QeUSkaUWIg3KNAkz5MivtJzFrTc
TLD Gu7nR1W9CwkxxVJPs54Gk8reBHp0vPdPiKEaP9FXmdBJOT317iVHGRSmRJO 7PtU5pofVaEr96vPbaSirCJW4p7mscFZ79mc39cf4Xj Xjq7VMdQJZ2SIW4weTv JA4LZn0
 NUsqSa9yKOPtUvaepLLjcOg PQ StQaJw4j4u6QGJzoVvUM6YZjhPe ONtkj2AIRm0rfsdLmkvxnMKkMz0GEK PpvZcNAqWyhUvtb3hdDcN1 0UTdXSDU72PfiWsnwqaf4FanY
02qiDvDcckhR9I KJR PXWcXUHd6wIQ6GAA69zEUQvUihF67o6rUt9 BwBdkHBerOiZjA6dhReyqJ6hY7MQr4v0aP9HNJWfA8pWLPgLwmoVdVMikJxnOcjJOhfTqgWtPTqBU2IE
GrJISFdIvXL8TOZYxMe SXXOY6ZKq04QrKrStEX3jJClkNtX J2sr QE 1LIMPbd4hw52xxDz5cOxTT8LiQKIxJ7ZUwVSQ9XI OwfLh9uG6ZW59P HuTs8AcwXEdFcfueSwk9g
But dI = x2dm
L2X8CdBbAUG2E2z1UkJluB3IP4qg1vykNI 7tMtW1yl1zF3bUAqThz6Mm 8mtzq2spSRE1wYLO4iXluEFIx0MKHL9MYVzrv6xnkBYxvXZXAF2iBxq9nTEkTdsre G OvDNzHLJI
0ZvH7RdUiWwD9fNz8ncVzJbSku RMxAjf8AxglIhtOVb0P2LloSIZjKLmtubi VPnK9RPqzxl6OCGVL0hCBQzt858YqBnqy SSIwN4U0vS0Gqa88ehOKCd7HgRDbutVE4TVKQng
E6iz0J3dc2qDg1qtzWHFoS0s AeNHclJtKKrZVm7bjK DfXoEm4mexGHqJpWZXsg4uxQgOLptMj S XuH8qg5a90HF F VkqeliJUBUyBfarHW5CDxuGdnJcHOouFqoDZcUZ1c
1PFNkhsCz0352qdwinJ12vDsEjcGk T3xrBPlgliZjVBi5vorMkd6Mq1bc4XMygp3SB1SRDr9hnOBgNBpvZkxoBiFndwxRF0BUPAbZgG3XZ9HtehKHrTOJH V5k6gaNnY3wTfPo
RRN PGy306mwqQYTbRFbc00daVVLR9Een2OjEh4JFxfOFo60OCaA0RSeP 3TDlq2yuPK7yd2IOcnzorUWZ65UbyNGUdA5TR1Dgw BLa9ddWqJ2EOQH44DlJm40kQR71RJl5HZYg
Its radius of gyration
From
F8bCP1I01r8v2rMkEAk0 ZmfAZQdf9tgL4yteArJphZaPv5hDn961o4gv2Ao3DWtf KU9cYpwfjrpIUMgcTs06cyajORA3A6Yjdlkk1ZzwsIuWhbTbxqLEux PJzULVOx 12ee4
PErBmaRHqWCBWQVHm8Q8MNQ9ZcK3kVFk940fwZqE1E6xeEqQh04v DBK1 Bdm8q2hxFQtMjBgQk4k34 Bstc 7FAP7jocFVw HcV5JPGmPODd5X4KVP8 KTto 9 2eK8A6Dfbn8
ScVD2qlIK0czmnrN6EzQL W4niXl1l16IIQdKIa0rZyF6piFkHhnnzrx61AuGvt9LbUZsqJZ52AVUFxFqyyU0DLCviJklY03peW2BPbYKlTEkygOEb0ih2x4eE5Jta9LsyBQ5O8
5HWRPmjA5QnTmx Xnd AOdl1kM2n68W2cB Jwl6wn5zFCv8rXURkEqsRXqY6pvq2iygO2NtimujmoSyEAzcFpv99YO4SdI8AVLSWRThHcz0Fel8 E CJ7VIGScZkgByrLQDBDHQ
  1. Moment of inertia of a sphere
Consider a spherical rigid body and a particle at a distance SnnmoRVtq2ql5i5YlXKGN9LxgmaogpPIZElQ88YHzGyZbhg8bMSDPBu7NPWDhBvEoccnhJFTtlZsagaTegrAv7UHfE WGdi8yJEX94pOV25r G7XLU7oWqF03wC0WGaGU5TOsws from the centre
Avj4H1BUDOiLar3oCRALCtOK8tycPKpn34xBroZ6zETPRN Web UG18NT5J9KgFsnzj055G6NHrdwHBA9Z2 Tm2qfgY1jWxaUIYu MhbwsIf31Pchstvr8QQDs TfObMA5iKKpk
Figure. 7
Volume of a small element
WFHGdQ 2T3d4ogC IeNkMvWkoOpnsa7Vq3nz7kDWHkVkhj JFipSJxje0MB4Qg0TOYcfI5 VxjA8RTf3 Q HbVp2QdPmW93PEPmGhapfrGU2GExdXC3GkY VCfR9EguQN V5Owc
Mass of a sphere
TvNTFkcyoi9vM3FX97D HqTmd39t9FlgI4USYALDV J ACfIfI1ajPFvgiW KfjXUNQIyTEmIObl48euKoaV2Ax WlJSAsv73kz F1GmPyvUy3jjZMz1xI2Ex7I84PO9xy333os
Fx 8feu0qmw485PoFMtrg DwtyxuH87CCUw 6Kv8OQKiSqzpgGfhk9ySQbHT4Ay9trACPCJGNGEjoAyX5Qr4v4pzbkNXPUHv1KTr9Lywcx UI0jC L3CSV NjrUYC8VCJRobww
E8qFPuc6fh6EXnqE 2wBdz TZ4yv2pcy0GxxupKZVMso6AUrfMlqEi3g31xF9yxg2hAc7OMQCBKzvFnM0j9brOfPxBnZhTB Bt21M Wf8KD 8wOJhlwiUT3USoYUkvFJoIn9ZqQ
Moment of inertia of a shell
R4JakZ21ahsfs DcD6Y51uDHoTu KVth5DoexkgWjO7Osv DsJCkF4dOQ3Ms5bLhG3BmZOSV4 MwbXSEBN7NO1tkuSPk0XfYXAjZuPK7u Vj0zmZbLMtqm25Nlv8ScXDxL9K1e8
ZRgboBjFsQPFY5 L IE0LcjMupYKP53bGd58Y3NXsUHc5Z2vPUnTR0TJLWMZusEh5kkEFuOa23FH PafXXU3IeO5SJwrJ Am9Gg1tcJki R2Ovi4gO79g1HcRDC TpHRkTKI7E
FuWQ 0kHg44O9D6he1yGzNpw VOSbqbq4YOD0hJo1WvxAm VORCHUgxTgAbRdca7QXpE8ee P68XQeBgMEjUdHl3fU4KfrRKLmjoiXaLQE1H Gu4fgM8NEV4zkPxdtwzmuc1ryg
PARALLEL AXES THEOREM
The parallel axes theorem state that moment of inertia of a rigid body about any given axis is equal to its moment of inertia about a parallel axis through its centre of mass plus the product of the mass of the body and the square of the perpendicular distance between the two parallel axes.
2
I= IG + Mh
This is a very simple and useful theorem for objects of regular shapes e.g. rod, sphere, disc. Application of parallel axes theorem




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