HEAT-4
Problem 98
A mono atomic gas initially at the temperature T = 25IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and pressure of 2 atmospheres is expanded to a final pressure of 1.0 atmosphere.
  1. Isothermally and reversibly
  2. Isothermally against a constant pressure of 1.0 atmosphere. Calculate for each case:
    1. The final temperature of the gas
    2. The increase of internal energy
Problem 99
The figure below shows some details concerning the behavior of a fixed mass of a gas assumed to be an ideal one in a petrol engine. The gas starts at A with a volume 5 Image?w=73&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw, temperature 300 K and a pressure of 1 . In the change from A to B it is compressed to volume of 1 Image?w=73&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw, the pressure rises to 1.5 . And temperature 630K Image?w=124&h=55&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
ImnRPD2y Vt H6Q95BoUPJwdEYGtq71t8glB CGqyZHft1VjS0UnEpT6oBIcNQGJ5XBSMTljIReQAgSz3ox2ChIEm7TDJoVWWuVRHtDo2HkArkd12IPBCR5 ZBDtU2LdHPhkU
  1. Using the equation of state for an ideal gas, find the number of molecules in the fixed mass of a gas.
  2. In the change from B to C the temperature of a gas rises from 630 K to 1500 K. The molar heat capacity at constant volume of the gas is 21F4KWU9IIQvJ2AKpjpwCvjZtaSClCORII6nShlXApAlPcfYIp59T0h61wFJE GiTRPvD7GHE HIi6TeN40kf7j2 W1FlYxpcHEky8 RoKfG8Mzgm9 NiWGODIk266teu5gxzR DU. Calculate the internal energy of the gas. c) How much work is done by the gas in changing from B to C?
d) In the change from C to D, the gas expands to its original volume; the temperature at D is 680
K. Calculate the pressure at D.
Problem 100
The figure below shows a sample of gas enclosed in a cylinder by a frictionless piston of area 100LsZ1UKe1Xeni38mWj52gY7HJHjPXJmphoxANTOkj79RHZh7uTPm7tm1aqdPKOeWBzKJ16OHBG6YrA3oEo2tQmy EbAkdvBZJ06MwnCR FmnTzd2lQDu7eOu8g7cQBoxmN29f1qc. The cylinder is now heated, so that 250J of energy is transferred to the gas, which then expands against atmospheric pressure of 1.00 x X NNNjlXopW8jU0vSqVUwcU OD EUrr MIF5FW 1Cb9ZUBiE8YkvaigGlFtDpOj2u5wDuJ5zD4n0 FdTmGCSIqTkUJ95jCKLf6xj0sJgGtgnm YczGtm3o4RoYoNWuXICMuCNc0. And pushes the piston 15.0 cm along the cylinder as shown
DHmqNa43Douqfc6LOlHhi5dFuAOVN9Bs2rrQlgwxx2uu Kj8XFZ3kA9AzuW4mFDZ5PI1au9LAwJ65S3eOta66hwezxr1SfOVUW03j7vnrtMx7keeN4d4enGorgGkCWaf 6hqWg
Calculate:
  1. The external work done by the gas
  2. The increase in internal energy of the gas.
Problem 101
When 1.50kg of water is converted to steam (at 100IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM) at standard atmospheric pressure of 1.01 Image?w=84&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw, 3.39MJ of heat are required. During the transformation from liquid to vapor state, the increase in volume of the water is 2.50RhDLl7auLl5LVD4h0XqJh2CXnhymO0ILTM9ZK4d6TE4oFSDitZuazTwmSoX3jS0nM0HuSxYm Q9 NIS2da1JCZhPtQaVAxwM4X6 3Ok7zFx25E1xIWBGeR4qBDiNuMwctKSrXno. Calculate the work done against the external pressure during the process of vaporization. Explain what happens to the rest of the energy.
Problem 102 A fixed mass of gas is cooled, so that its volume decreases from 4.0 liters to 2.5 liters at a constant pressure of 1.0 Image?w=42&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcwPa.
Calculate the external work done by the gas.
Problem 103
The specific latent heat of vaporization of steam is 2.26 MJ . When 50 of water is boiled at standard atmospheric pressure of 1.01 Pa, 83 of steam are formed. Image?w=216&h=51&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Calculate
  1. The mass of water boiled
  2. The heat input needed
  3. The external work done during vaporization
  4. The increase in internal energy
Given that density of water 1000 RI2mDMMFa9IiJaZeAIJ6koEhbmxr7li4jIRzO7O HvGMQENPX ZBn2ILlJ13IKQ1kc35f9JuvNjMMA7GCrjTkyinMpEzIDQ0tm8Jcy8SWr2Xu80vDFdzts8CxRxrxw4NNwhnj 0
Problem 104
56.0 Image?w=51&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcwkg of nitrogen is to be heated from 270 K to 310K. When this occurs in an insulated freely extensible container, 2.33 Kj of heat is required when contained in an insulated rigid container, 1.66KJ of heat is required. Calculate the principal molar heat capacities of nitrogen.
Problem 105
The specific heat capacity of a diatomic gas at constant volume is 0.410 KJ SfpMav7qdwpaUDPbqhPz DYw ND2a F6ZHLvhvdHNPiB0R6 Xdggx2jWCv1SSbBaRgYCvSSBnwqc1RKJ40640epJ4mHwdXQv OFK5kQb2EOOY6 2dP GsuvB4Iu03UGoWEzaPQ
Calculate
      1. The specific heat capacity of the gas at constant pressure.
      2. The specific gas constant for the gas.
Problem 106
The amount of heat required to raise the temperature of 3.00 mole of a polyatomic gas, at constant pressure, from 320 K to 370 K is 4.99 KJ.
Calculate
      1. Image?w=69&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
      2. The value of 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc
      3. The heat required to raise the temperature of 4.00 mole from 300 K to 400 K at constant volume
Problem 107
Argon has a molar heat mass of 40 kg and a principal molar heat capacity, at constant volume, of 12.5 Calculate: Image?w=137&h=54&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
      1. The valve of 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc
      2. The specific heat capacity at constant volume
      3. The amount of heat required to raise the temperature of 1.00kg of argon by 80 K at constant volume.
Problem 108
2.00 mole of nitrogen, at 300K are in an insulated, freely extensible container, and the pressure outside the container is 1.00 . The principal molar heat capacity of nitrogen at constant pressure is 29.0 Image?w=116&h=55&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Calculate:
  1. The heat required to raise its temperature to 340 K.
  2. The increase in volume of the gas during this process.
  3. The external work done
  4. The internal energy change
  5. The heat required to effect the temperature change at constant volume
Compare (d) and (e) and comment
Problem 109
The piston of a bicycle pump is slowly moved in until the volume of air enclosed is one-fifth of the total volume of the pump and is at room temperature (290K). The outlet is then sealed and the piston suddenly drawn out to full extension. No air passes the piston. Find the temperature of the air in the pump immediately after withdrawing the piston assuming that air is a perfect gas with 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc = 1.
Problem 110
A fixed mass of gas, initially at 7IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and a pressure of 1.00 Image?w=84&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw, is compressed isothermally to one – third of i
ts original volume. Calculate the final temperature and pressure, assuming 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc = 1.40
Problem 111
A fixed mass of gas is taken through the closed cycle A B C D A as shown in the figure below Image?w=113&h=23&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
 NUkgAV Vt2I39R3J8n2UT08jnsyE7aW0uTUjDqAag LNv4F4N49GHeHv8b6a2CiWDCNEW3LTRNgsdy8xW PVqMQI9DsChwD0OfhBKDpRgxhHbfV953pe4nFIBSRCu164JpTUzA
  1. Calculate the work done in the cycle.
  2. How much heat transferred in the cycle?
  3. Is the heat absorbed or emitted by the gas?
Problem 112
One mole of water, occupying a volume of 1.8 , is turned into steam in a boiler at a temperature of 373 K and a pressure of 1.0 Pa. The volume of steam generated i
s 0.031Ym3AMwsrFVL3TX0YobZ61CwpEg4OWuf3CrBp755fC7kQDUTcxmRKymp05MA9HE3HMUVl MPMlnd4RnG42i6wLulGGEf3LeEqcWll9BLSSACo5g 116YyF2p9 RtY D5fbU4jWNk. The energy required is 41,000J. Image?w=84&h=55&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Calculate the work done (in Joules) against the atmospheric pressure in the production of steam.
Problem 113
The figure below shows water changing into steam at constant pressure and held in a cylinder by a free – sliding piston.
1.00 kg of water at 100IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM is changing into steam at atmospheric pressure.
Calculate:
      1. The external work done
      2. The increase in internal energy
      3. What happens to the internal energy absorbed during the vaporization process?
Given that:WN3PklP8IqrmvumLV1c3ppLLSIdtJULJ733tqHbfGMm4sdL97P9QvhvUdolgBiAtvA5dVwZEluGQc1trgAjA9S6Q7aPpNk0xiYoWILT2elL9j5VbUZySjAp8lruPgxNQcWqVwk8
Density of water at 100Image?w=104&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Density of steam at 100 and at atmospheric pressure = 0.59 Atmospheric pressure, = 1.01 Image?w=42&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw Pa. Image?w=17&h=51&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Specific latent heat of vaporization of water = 2.26Image?w=84&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Problem 114
At a temperature of 100 and a pressure of 1.01Image?w=42&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcwPa, 1.00Kg of steam occupies 1.67 , but the same mass of water occupies only 1.04 . The specific latent heat of vaporization o water at 100IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM is 2.26 Image?w=147&h=101&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
. For a system consisting of 1.00kg of water changing to steam at 100 and 1.01 Pa, find :
  1. The heat supplied to the system
  2. The work done by the system
  3. The increase in internal energy of the system.
Problem 115
The ratio of the principal heat capacities of an ideal gas is 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc, and the molar gas constant is R.
Show that the molar heat capacity at constant pressure of the gas is
YBjej2PbqCHBsLOxuhiIWm8plazmB93FDJLKhJktBU3Om33Hpuyr3yijaCK5a2VZotP4qs3itGMTs2tlzSyiG9S79he01c0eJUZpnP5kcM5FJaOXlrv KjCbN T2kpBi3HDEijU
Problem 116
The specific heat capacity at constant volume of a certain ideal gas is 6 x 0U5lTxwzjvgq5QiyMEOHF Za9wUnX0S4CCyHNy VEJaZzw5YNmZQ12U6NU YjaJ6Mg8yP8DLfNHxJDWUK 2EUwUJ67QtorobWiyRNqCToSPEkIYnz0Fnw5RCsP9SCpyBXK0Rjqg and is independent of temperature.
Find the internal energy of 5.0 x HnYProypu6V435XWwNN0u MP NX0xM6iwL2wDK1ZB4Mk15D3se8zfch0GWUHptqHp PzzeqiwDBPsqNfIRy7aEYnz1RuwWnUnnQ9xK5wapPXvkac4AWd VDSeRhzc Ue0GjjUigkg of the gas at 27IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM.
Problem 117
QIdw S5HeljkeHNOQ8fDg5QfQ0YMBM NOv13UT MU0fzRVGQINXhr MaDfGySWwOW4D EbW1O8O69w4Y2a0whLNJSzmtevO 3tvsEDJu6jV OL3EsGWM5fdCjmRyrRfjEoH 5Q
Helium may be assumed to behave as an ideal gas. A sample of 20 moles of the gas are taken through the cycle of changes ABC as shown in the figure above.
( i) Use the data from the figure to show that the change from A to B must take place at constant temperature.
  1. The temperature for this change is 300K. Wha
    t is the temperature of the gas at C?
  2. What energy process takes place between B and C?
  3. The change in internal energy of the sample in the process from B to C is 56KJ. Calculate the molar heat capacity at constant volume for helium.
  4. Calculate the work done during the change from C to A. State and explain whether work is done on or by the gas during this part of the cycle. Justify your answer.
  5. Determine the value of molar heat capacity at constant pressure for helium. Show Clearly how you arrive at your answer.
  6. Use the figure to estimate the net work done during one complete cycle.
Problem 118
A fixed mass of an ideal gas has a volume 2oM0SARSSgbyq Bh57OXMeAYmH4Fj1NgVdJ2myxPLFS2u8dVgJzBHVo7t6TnFzamYWu0AtauB OV 8fg2hFayLxaW5 KKM5 KnHT GDtWjJ3MYXIRobcCW9TZPh 3HKIkbEUHRs at an initial temperature of 300 K and an initial pressure of
1.2 Image?w=42&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcwPa.
It is made to undergo the following cycle of process.
        1. Isothermal expansion from its initial volume 2oM0SARSSgbyq Bh57OXMeAYmH4Fj1NgVdJ2myxPLFS2u8dVgJzBHVo7t6TnFzamYWu0AtauB OV 8fg2hFayLxaW5 KKM5 KnHT GDtWjJ3MYXIRobcCW9TZPh 3HKIkbEUHRs to a volume 2 Image?w=17&h=48&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
        2. Expansion at constant pressure to a volume 4 C. Isothermal compression
D. Compression at constant pressure to its initial state. (a) Sketch a cycle on a P – V diagram
(b) Determine:
( i) The pressure at the end of process A
  1. The temperature at the end of process B
  2. The volume at the end of process C
Problem 119
A fixed mass of an ideal gas at an initial temperature of 20IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and at a pressure of 1.00 Image?w=42&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcwPa is compressed until its volume is one- quoter of its original volume.
Calculate the final temperature and pressure of the gas, assuming:
  1. The compression is isothermal
  2. The compression is adiabatic
Given that Image?w=76&h=45&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw = = 1.40
Problem 120
In a diesel engine, fuel oil is injected into a cylinder in which air has been heated by adiabatic compression to above the ignition temperature of the oil. The ignition temperature of a certain fuel is 630 , and the air enters the cylinder, which has an initial volume of 5.0 Image?w=73&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw at a pressure of 1.0 Pa and a temperature of 28IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM Image?w=72&h=51&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
  1. What minimum compression ratio (the ratio of the initial to the final volume of the cylinder) is required to heat the air to the fuel ignition temperature?
  2. How much work is done in compressing the air
    ?
Given that for air 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc = 1.40
Problem 121
(a) A cylinder fitted with a piston which can move without friction contains 0.05 mole of a mono atomic ideal gas at a temperature of 27IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and a pressure of 1.0 Image?w=42&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcwPa.
Calculate:
(i) The volume of the gas.
(ii)The internal energy of the gas
( b) The temperature of the gas in (a) above is raised to 77IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM, the pressure remaining constant.
Calculate:
(i) The change in internal energy
(ii)The external work done
(iii) The total heat energy supplied
Given that molar gas constant = 8.3WRqzsH7TqHHUDv8DBHsboxqJSPMWSuNXyPtZ Y HqCgO7EsLM54xddvdlpWs6u4YXE5EjYqXRfJI2q0fW5NSn3EMvq7PmjTdkfFvCWwVX7T7Kw65rMuhm3XKuuRv8CxyrTjDEpw.
Problem 122
  1. Give one practical example of each of the following: (i) A process in which heat is supplied to a system without causing an increase in temperature.
(ii) A process in which no heat enters or leaves a system but the temperature changes.
  1. What happens to the energy added to an ideal gas when it is heated:
    1. At constant volume?
    2. At constant pressure?
  1. Deduce an expression for the difference between the specific heat capacities of a gas at constant pressure and at constant volume.
  2. If the ratio of the principal specific heat capacities of a certain gas is 1.40 and its density at S.T.P is 0.09KWHDtKd1yXxGSbrevP3TZDU5esgtWeju 6xNHEwI3RvTllkCKDN0 BfhBg3NefFR4sk6w8a1 I2RpZQErOD0NG 9zcUX4GITAuOgoPciRzhmsF0PjEBt0kFpIcIddu LBj3n6U, calculate the values of the specific heat capacity at constant pressure and at constant volume. Standard atmospheric pressure = 1.01 x
BGT7c50cbrD XzMHb5KLQSJD1fr LJ6 GAmxlUB0pkm6TRNn6B BAlbe0AWYrqSQ 7frBHz1F5dW3olueVsst5LO3fH9KfAxkxOYGA7Bz1kSjKmXwB1ZeK0ca4BssNzQiPnGeSQ
Problem 123
A steel pressure vessel of volume 2.2 contains 4.0 Pa and temperature 300 K. An explosion suddenly releases 6.48 J of energy, which raises the pressure instantaneously to 1.0 Pa. Assuming no loss of heat to the vessel, and ideal gas behaviour, Image?w=227&h=75&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Calculate:
  1. The maximum temperature attained
  2. The two principal specific heat capacities of the gas.
What is the velocity of sound in this gas at a temperature of 300 K?
Problem 124
  1. Explain why an ideal gas can have infinity number of molar heat capacities and define the principal values.
  2. A thermally – insulated tube through which a gas may be passed at constant pressure contains an electric heater and thermometers for measuring the temperature of the gas as it enters and as it leaves the tube. 3.0 Image?w=74&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw of gas of density 1.8 KWHDtKd1yXxGSbrevP3TZDU5esgtWeju 6xNHEwI3RvTllkCKDN0 BfhBg3NefFR4sk6w8a1 I2RpZQErOD0NG 9zcUX4GITAuOgoPciRzhmsF0PjEBt0kFpIcIddu LBj3n6U flows into the tube in 90 seconds and, when electrical power is supplied to the heater at a rate of 0.16W, the temperature difference between the out let and inlet is 2.5 K. Calculate a value for the specific heat capacity of the gas at constant pressure.
Problem 125
(a) Explain clearly and concisely why, for a fixed mass of a perfect gas:
  1. The internal energy remains constant when the gas expands isothermally.
  2. The heat capacity at constant pressure is greater than the heat capacity at constant volume.
(b) A vessel of volume 1.0 contain an ideal gas at a temperature of 300 K and pressure 1.5 Pa. Calculate the mass of gas, given that the density of the gas at temperature Image?w=222&h=75&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
285 K and pressure 1.0 Pa is 1.2
(c) 750 J of heat is suddenly releases in the gas, causing an instantaneous rise of pressure to 1.8
Image?w=42&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcwPa. Assuming ideal gas behavior, and no loss of heat to the containing vessel, Calculate the temperature rise, and hence the specific heat capacity at constant volume of the gas.
Problem 126
(a) What is an adiab
atic change?
A vessel of volume 8.00 Image?w=73&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw contains an ideal gas at a pressure of 1.14 Image?w=42&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcwPa.
A stopcock in the vessel is opened and the gas expands adiabatically, expelling some of its original mass, until its pressure is equal to that outside the vessel 1.01 Image?w=42&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcwPa. The stopcock is then closed and the vessel is allowed to stand until the temperature returns to its original value; in this equilibrium state, the pressure is 1.06 Image?w=42&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcwPa.
(i) Explain why there was a temperature change as a result of the adiabatic expansion.
(ii)Find the volume which the mass of gas finally left in the vessel occupied under the original conditions.
    1. Sketch a graph showing the way in which the pressure and volume of the mass of gas left in the vessel changed during the operations described above:
    2. What is the value of 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc, the ratio of the principal heat capacities of th
      e gas.
    3. What can you deduce about the molecules of the gas? Give your reasons.
Problem 127
3eU5791ZXn1oiS3n3KRgiBRGwhvmXbzncbIOWv G1E4VkJ5IaI9H7P3Kn75HQuz3SyG2UZF4IRzTDkzvNuAbYpO8GvqS8wahNLfoo4BBC2vstREIpJPf ZMIcC1DvLNuC1HcEaU
The diagram above represents an energy cycle whereby a mole of an ideal gas is firstly cooled at
then heated a constant volume Y1yGQe9QLvfSMat94f4QV3GMdaGK8kW9uZZ4xHBWq0zgWY1SjaRTyGFvcbP MfJCbc4xyoKwaLC1v8hpkPO8YHCahklHf4jTaR PDogtM9vlBVHuBcYmWmAY8 OFHktw7uSB8fg and returned to its original
stateImage?w=176&h=55&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
( a) Calculate the temperature of the gas at A, at B and at C
( b) Calculate the heat given out by the gas in the process A KWHDtKd1yXxGSbrevP3TZDU5esgtWeju 6xNHEwI3RvTllkCKDN0 BfhBg3NefFR4sk6w8a1 I2RpZQErOD0NG 9zcUX4GITAuOgoPciRzhmsF0PjEBt0kFpIcIddu LBj3n6U B
( c) Calculate the heat absorbed in the process B KWHDtKd1yXxGSbrevP3TZDU5esgtWeju 6xNHEwI3RvTllkCKDN0 BfhBg3NefFR4sk6w8a1 I2RpZQErOD0NG 9zcUX4GITAuOgoPciRzhmsF0PjEBt0kFpIcIddu LBj3n6U C
( d) Calculate the net amount of heat transferred in the cycle.
Given that R = 8.3WRqzsH7TqHHUDv8DBHsboxqJSPMWSuNXyPtZ Y HqCgO7EsLM54xddvdlpWs6u4YXE5EjYqXRfJI2q0fW5NSn3EMvq7PmjTdkfFvCWwVX7T7Kw65rMuhm3XKuuRv8CxyrTjDEpw. and
4HbndPcnQy WdXSsfQv3AN8MzTfSYUYARj727ouiXO3VyyWuTfFTqXi3W AF TWcXe E1I5iSrhEL5ORrpZ C0QbZJtfCen8t59pqfcXKjlfw3tdW2u3hWQtcH5OWQPbiTZgD8s
Problem 128
The specific latent heat of vaporization of particular liquid at 130IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and a pressure of 2.60 Image?w=42&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcwPa is
1.84 Image?w=89&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw.
The specific volume of the liquid under these condi
tions is 2.00
vapor is 5.66 . Image?w=229&h=55&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Calculate:
(a) The work done, and
( b) The increase in internal energy when 1.00 kg of the vapor is formed from the liquid under these conditions.
Problem 129
  1. Explain what is meant by a reversible change.
  2. A mass of 0.35 kg of ethanol is vaporized at its boiling point of 78IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and a pressure of 10
Pa. At this temperature. The specific latent heat of vaporization of ethanol is 0.95 and the densities of the liquid and vapor are 790KWHDtKd1yXxGSbrevP3TZDU5esgtWeju 6xNHEwI3RvTllkCKDN0 BfhBg3NefFR4sk6w8a1 I2RpZQErOD0NG 9zcUX4GITAuOgoPciRzhmsF0PjEBt0kFpIcIddu LBj3n6U and 1.6 respectively. Calculate: Image?w=100&h=74&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
(i) The work done by the system
(ii)The change in internal energy of the system
Explain in molecular terms what happens to the heat supplied to the system.
Problem 130
The graph below relates the pressure and volume of a fixed mass of an ideal gas which is first compressed isothermally from A to B and then allowed to expand adiabatically from B to C.
 XvnJSEbXF3Z5p9dkd1ygjI43n Les8jvEk7LThC7Fa991F3obnVP6bnhb4iWlJ GA4HYAfGSmqPvUKROJ OdmaM7VIKlMCoVMlY 9DU28DK5fk4aoc5BVSzfaRxqk05iWmJBcI
For each of the changes shown on the graph, state and explain whether:
  1. The temperature of the gas changes
  2. There is heat transfer to or from the gas
  3. Work is done on or by the gas
Problem 131
An ideal gas at 17IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM has a pressure of 760mmHg, and is compressed.
  1. Isothermally,
  2. Adiabatically until its volume is halved, in each case reversibly. Calculate in each case the final pressure and temperature of the gas, assuming RzPbs FzNiPSRtoBtJpc5RI4QGZ1Gg728Dxj3S8SbSHwxifQVEKf5M0LHwHeYzHANFe7CheXYAJHWHs3QyB9WZTHi6JFhCNppMZmjn0V9GpBC0Bt0jHN4u AKRqaRenRsz3aakc =
2100Image?w=124&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw = 1500RtDj0K39N P36S6oRSmM EHsj54ZtFeQZ7hzHxVVxI8OOy95HCq5PDnq7lNUUsUymRfVs7fy1fTvEv O5vtG3oeW1UHlo4DukWlaXPM828XKSXfiP4qakx3ZF2i ZPLCUeu8iGw.
Problem 132
  1. Show that for an ideal gas the
    curves relating pressure and volume for an adiabatic change have a greater slope than those for an isothermal change, at the same pressure.
  2. A gas in a cylinder initially at a temperature of 17IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and a pressure of 1.01
Image?w=84&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw, is to be compressed to one-eighth of its volume. What would be the
difference between the final pressures if the compression were done.
    1. Isothermally
    2. Adiabatically?
Given that 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc = 1.40
Problem 133
Given that the volume of a gas at S.T.P is 2.24 Image?w=121&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw and
that standard pressure is 1.01Image?w=90&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw, calculate the molar gas constant R and use it to find the difference between the quantities of heat required to raise the temperature of 0.01kg of oxygen from 0 to 10 when. Image?w=64&h=23&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
  1. The pressure is kept constant
  2. The volume is kept constant
(Given that relative molecular mass of oxygen = 32)
Problem 134
    1. By considering the expansion of an ideal gas contained in a cylinder and enclosed by a piston, show that the work done in a small expansion is equal to the pressure times the volume change.
    2. An ideal gas, at a temperature of 290 K and a pressure of 1.0 , occupies a volume of 1.0 Image?w=77&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw. Its density conditions is 0.30 . Image?w=146&h=75&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
It expands at constant pressure to a volume of 1.5 . Calculate the energy added.
    1. The gas is now compressed isothermally to its original volume.
Calculate.
(i) Its final pressure and temperature
(ii)The difference between its final and initial internal energies. Given that specific heat capacity at constant volume of this gas =
7.1 Image?w=115&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw.
Problem 135
A litre of air, initially at 20IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and at 760mmHg pressure, is heated at constant pressure until its volume is doubled. Find
( a) The final temperature
  1. The external work done by the air in expanding
  2. The quantity of heat supplied.
Assume that the density of air at S.T.P is 1.293Dhx40OwdWFEtRe9sNTyZOmyq8o1rAuj2Y WtXlvMoqCCL 8Ppv5np AU9xVGaPEDuSkEa3MAjG74Cs4Ms5hDbbHoVdP9YfUsUVBymLroCS8FGyfKC2DzzbkJBskk8aAfQ2bjHpk and that the specific heat capacity of air at constant volume is 714RtDj0K39N P36S6oRSmM EHsj54ZtFeQZ7hzHxVVxI8OOy95HCq5PDnq7lNUUsUymRfVs7fy1fTvEv O5vtG3oeW1UHlo4DukWlaXPM828XKSXfiP4qakx3ZF2i ZPLCUeu8iGw.
Problem 136
a) Deduce an expression for the difference between the specific heat capacities of an ideal gas.
(b) If the specific heat capacity of air at constant pressure is 1013RtDj0K39N P36S6oRSmM EHsj54ZtFeQZ7hzHxVVxI8OOy95HCq5PDnq7lNUUsUymRfVs7fy1fTvEv O5vtG3oeW1UHlo4DukWlaXPM828XKSXfiP4qakx3ZF2i ZPLCUeu8iGw and the density at S.T.P is 1.29Dhx40OwdWFEtRe9sNTyZOmyq8o1rAuj2Y WtXlvMoqCCL 8Ppv5np AU9xVGaPEDuSkEa3MAjG74Cs4Ms5hDbbHoVdP9YfUsUVBymLroCS8FGyfKC2DzzbkJBskk8aAfQ2bjHpk, estimate a value for the specific heat capacity of air at constant volume.
Problem 137
(a) What is the importance of the ratio of the specific heat capacities of an ideal gas? (b) A mass of air occupying initially a volume 2 U7VSY0ue7wLHSSo8h3IfD4yNJwbU5n4apMkMMroQVqZ0fkPVlP650zDorN472KfmB PM6ODney TvkqjXep7m0ZQ4Zmys9qbDFN1 7osMrc63c3Xd7rBG12r6HyoN5mFg41IaU at a pressure of
760mmHg and a temperature 20IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM is expanded adiabatically and reversibly to twice its volume, and then compressed isothermally and reversibly to a volume of 3
Image?w=74&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw. Find the final temperature and pressure, assuming the ratio of the
specific heat capacities of air to be 1.40.
Problem 138
Air initially at 27IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and at 750mmHg pressure is compressed isothermally until its volume is halved. It is then expanded adiabatically until its original volume is recovered. Assuming the changes to be reversible find the final pressure and temperature take 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc = 1.40
Problem 139
When water at 100IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and pressure of 101 kPa changes to steam under the same conditions, its volume increases by a factor of 1670 given the density of water is 960 Image?w=113&h=52&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw and 101 kPa, and its specific latent heat of vaporization is 2.26
Calculate
  1. The heat supplied to convert 1 kg of water at 100IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM to steam at the same temperature.
  2. The work done when 1 kg of water turns to steam at 101kPa pressure.
  3. The increase of internal energy.
Problem 140
A fixed mass of ideal gas is contained in a cylinder. The cylinder volume can be varied by moving a piston in or out. The gas has an initial volume 0.01RhDLl7auLl5LVD4h0XqJh2CXnhymO0ILTM9ZK4d6TE4oFSDitZuazTwmSoX3jS0nM0HuSxYm Q9 NIS2da1JCZhPtQaVAxwM4X6 3Ok7zFx25E1xIWBGeR4qBDiNuMwctKSrXno at 100 kPa pressure and its temperature is initially 300K. The gas is cooled at constant pressure until its volume is 0.006RhDLl7auLl5LVD4h0XqJh2CXnhymO0ILTM9ZK4d6TE4oFSDitZuazTwmSoX3jS0nM0HuSxYm Q9 NIS2da1JCZhPtQaVAxwM4X6 3Ok7zFx25E1xIWBGeR4qBDiNuMwctKSrXno
. Sketch a pressure against volume graph to show the change.
Calculate:
  1. The final temperature of the gas.
  2. The work done on the gas.
  3. The number of moles of gas.
  4. The change of internal energy of the gas.
  5. The heat transfer from the gas
(Assume R =8.3 Jmol -1k-1)
Problem 141
Two identical cylinders X and Y contain equal volumes of ideal gas at the same temperature and pressure. The volume of each cylinder can be varied by moving a piston in or out for the cylinder. The gas in each cylinder is then compressed to half its initial volume: X is compressed isothermally whereas Y is compressed adiabatically. Show the changes on a compressed adiabatically. Show the changes on a pressure against volume diagram and compare the energy changes for the two gases.
Problem 142
A motor car tyres has a pressure of four atmospheres at a room temperature of 27IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. If the Tyre suddenly bursts, calculate the temperature of the escaping air. Value of 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc for air is 1.4
Problem 143
A molecule of a gas at 27IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM expands isothermally until its volume is doubled. Find the amount of wo
rk done and heat absorbed.
Problem 144
A cylinder fitted with a movable piston contains 3 moles of hydrogen at standard temperature are made and pressure. The walls of the cylinder are late by having a pile of sand on it. By what factor does the pressure of the gas increase if the gas is compressed to half its original volume? Given 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc = 1.4 Problem 145
A quantity of air Image?w=114&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw is compressed
  1. Slowly and
  2. Suddenly to one third of its volume. Find the change in temperature in each case.
Problem 146
A Tyre pumped to a pressure of 6 a.t.m suddenly burst. The room temperature is 15IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. Calculate the temperature of escaping air.
Take 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc = 1.4
Problem 147
A litre of air, initially at 20IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and at 760mmHg pressure, is heated at constant pressure until its volume is doubled.
Find:
  1. The final temperature
  2. The external work done by the air in expanding
(iii)The quantity of heat supplied.Assume that the density of air at N.T.P is 1.293 Image?w=101&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw =
714 9k7 6 B1V98nTSAS2WhrSGtkttUl0gRXBhrouni1TUmHX4ve115TavQFn IHga4xKsdLbmO9YF9KB2B TQxXeP4Qhlzg7zOnEV8 GCoP 5bdXP2GQKlPHsk5hO9 F270aIiuU
Problem 148
A gas is suddenly compressed to one-half of its volume. Calculate the rise in temperature, the original temperature being 27 . Take = 1.5 Image?w=61&h=23&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Problem 149
A certain volume of dry air at N.T.P is allowed to expand four times its original volume under. i) Isothermal conditions
(ii) Adiabatic conditions
Calculate the final pressure and temperature in each case. Take 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc = 1.4
Problem 150
10 moles of hydrogen gas at NTP are compressed adiabatically so that its temperature becomes 400IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. How much work is done by the gas? Also find the increase in internal energy of the gas.
Given R = 8.4 Image?w=118&h=23&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw and = 1.4
Problem 151
Calculate the work done when one mole of a perfect gas is compressed diabatically. The initial pressure and volume of the gas are ZYxAwXeZ 2ERefVf97sIniG8OQnYVvOZp1FBApPMKt8nRGflW3X4XiE4QP P4FfymLifozr6SltmCCek716R2VymaqqDrDmIyOTINKu6QkAEns6KZzuLf4 EdmbckhgjXf16Gq4 and 6 litres respectively. The final volume of the gas is 2 litres. Molar specific heat of the gas at constant volume is ITCKI S8EWSaT15tMyLluEzgSAsgmFZDIR KK1XZkOyP7wf5NiV6oFX86 CRP TK4WTGA PdXqKtZL9Z2VOrk Ok2PSQKRMQ8DzISV9h3MzVkx79Dh 7GvHbUcyAff6RGqpU3Fk
Problem 152
A cylinder contains 1 mole of oxygen at a temperature of 27IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. The cylinder is provided with a frictionless piston maintains a constant pressure of 1 a.t.m on the gas. The gas is heated until its temperature rises to 127IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM.
(i) How much work is done by the gas in the process?
(ii)What is the increase in internal energy of the gas?
(iii) How much heat was supplied to the gas?
Given that HKmcM95NcK3FrFOnn5yX6s8UvuUP Ac6vTWDV8DXIBypkv9k7yL4p5AoXXheOcz1PdVm0ARR9WPMB1xoajHg4F2RErBK9rooju 3nF3DWWUCCI5ZeSrUE W2xa4EFQlZXCs3BE0 = 7.03 cal 4zseZEO 2RsX9kWl5pc9PDE8CP79vpoPiRwaWj78LWX7Lki1tijfEJkFdPSRk6RqhpM8HYG6k SmSe1za PKpUM8mQYvrogoIZR15rVvZordn7joKcFEvABiAp40UOsuVqiMo9E and
R = 1.99 cal 4zseZEO 2RsX9kWl5pc9PDE8CP79vpoPiRwaWj78LWX7Lki1tijfEJkFdPSRk6RqhpM8HYG6k SmSe1za PKpUM8mQYvrogoIZR15rVvZordn7joKcFEvABiAp40UOsuVqiMo9E
Problem 153
Two moles of helium gas Tm H0EgQyoBC9aUaJSILjzJjJUz 4O0 YeCW8H8nVnMpfopEumetmYQ617iXu9h53wbhJLcOY PABpKbOK6ZA9iI L5oZypWO JA4Z070 KkExrlNbHTLrftNOINGtsy5iLWgbo are initially at a temperature 27IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and occupy a volume of 20 litres. The gas is first expanded at constant pressure until the volume is
doubled then it undergoes adiabatic change until its temperature returns to its original value.
(i) Sketch the process the P – V diagram
(ii)What are the final volume and pressure of a gas?
(iii) What is the work done by the gas? Gas constant R = 8.3 S2lDXaBLA0 0IX NoEXt1agdi8B2kzkRunJVAQZtMphQRP3SUgPDLCET4JuzITOct5yO1530Hltf19K6rTiIZVTaGjnk6J49JWEXrwswQpwSjTSL3RKKs0eZY6JpPlDWnzfaFM
Problem 1542A2jaXmpnZhYR7QpjD1snmM1nNpUuqANhHsd284G8W2QUlkcjPLoqrdPNYb 26pYqMdM9 HlK5kDAiCzKgQT9IoZhODcVIehW6IqyCEO Xd1zCOOiYv0k0KwCXor2jEOQtGG0YE
Consider the cyclic process ABC on a sample of 2.0 mole of an ideal gas as shown in the figure below
The temperature of the gas at A and B are 300 K and 500 K respectively. A total of 1200 J of heat is withdrawn from the sample. Find the work done by the gas in part BC.
Given that R = 8.3J R2eoO0g1CwPoy0jMKmDITAu 97t Caj04EI5YY5P8 OsVHs1GffYZMwP5FeKJoPARr40o9d0IkE1F0nzzrOyfdaDqVxk0knNJYKqSLOFp C2knRBVAQSnFUOqVU45xI SUbCnU
Problem 155
A cylinder contains 3 moles of oxygen at a temperature of 27IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. The cylinder is provided with a frictionless piston which maintains a constant pressure of 1 atmosphere on the gas. The gas is heated unless its temperature rises to 127IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM.
  1. How much heat is supplied to the gas?
  2. What is the change in internal energy of the gas?
  3. How much work is done by the gas in the process? Given that HKmcM95NcK3FrFOnn5yX6s8UvuUP Ac6vTWDV8DXIBypkv9k7yL4p5AoXXheOcz1PdVm0ARR9WPMB1xoajHg4F2RErBK9rooju 3nF3DWWUCCI5ZeSrUE W2xa4EFQlZXCs3BE0 = 7.03 cal 4zseZEO 2RsX9kWl5pc9PDE8CP79vpoPiRwaWj78LWX7Lki1tijfEJkFdPSRk6RqhpM8HYG6k SmSe1za PKpUM8mQYvrogoIZR15rVvZordn7joKcFEvABiAp40UOsuVqiMo9E
Problem 156
An ideal gas having initial pressure P, volume V and temperature T is allowed to expand adiabatically until its volume becomes 5.66 V while its temperature falls to 9nLALvhS9NTUvlqNZcxhABKHkXiQrcDxPnUOKQ8iy5s2qtIG80z9XuKtVzlvjTE5JRmaI71qZtGOACt0bjxaCgHutq4SzSWiuqEwtWDj56KxLZtudG5RQNC5NKOo1MaAt72WSkE
i) What is the value of 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc for the gas?
(ii ii) Obtain the work done by the gas during expansion as a function of initial pressure P and volume.
Problem 157
What amount of heat is to be transferred to nitrogen in an isobaric heating so that the gas may perform 2 J of work?
Problem 158
In the figure below an ideal gas changes its state from state A to C by two paths ABC and AC
MnOFiBlLlW6F5wBUx ABGvw11o8LiI5V ZXmJ34Co8CHKLCXz1K Dgn4aXxAg9iMiwM1hslY3WyGLOPow6fbo6Q9x1CUYlXYMFxtZ1IqX4PtAiuEZgNQu7GzHC K YUe7u3HWOY
(i) Find the path along which work done is less
(ii)The internal energy of gas at A is 10 J and the amount of heat supplied to change its state to C through the path AC is 200J . Calculate the internal energy at C.
(iii) The internal energy of gas at state B is 20J. Find the amount of heat supplied to the gas to go from A to B.
Problem 159
As a result of isobaric heating by E76jgDpGjhiLxL3HzwXrSekaAnXkxURfaN ZtHRopGbf5otwYHIDzcH1lMFNtVS9Fu9tb HB5fMr8tQ9WvZOASfTCu0a BOQns19lFHS5L57co9cZVjfbiFA7rlT6Aip12WrpNQ = 72 K, one mole of a certain ideal gas obtains an amount of heat Q = 1.60 KJ.
Find:
  1. The work done by the gas
  2. The increment in its internal energy
  3. The value of 82X4qaGUE2uZRn3PFKMFxucONBK2NLwvEnEw VGKSA9k DmzM94Tx8nY0m0JepiV8bvIDgEDcwkow30hdw82V8L SUHfvujp4Pu1KNELI8szRLM6TWMQluCDAvL0rp3IO45wFHc
Problem 160
The figure below shows a process ABCA performed on an ideal gas. Find the net heat given to the system during the process.
Vbg37oe0KvCPETLekSzyREW8eip9PW17 KHZs0au3OHWEMgrcAaZMrELPmZVJRJ5Kv GyG7rei5Jq2wQ4vUs4R5ypsJWj3bw6SW4fEYWFcgaBvn7wrynOyQyanZaPpe5XMlZ1ko
Problem 161
In a thermodynamic process the pressure of a fixed mass of a gas is changed in such a manner that the gas releases 20 J of heat and 8 J of work is done on the gas. If the initial energy of the gas was 30 J. What will be its final internal energy?
Problem 162
Two different adiabatic paths for the same gas intersect two isothermal at Image?w=61&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw as shown
in the P – V diagram below. How does PSzHRZ3ccFkOz4hdEDfcEIHbCQODGVsPyEQvu83iHCg6p0cxBSRiLmif8Fi OXz ZZKz1EHxm JXRaVhSrOHNLlueh8cf4s3xw OyCROkkG CGw0CVAK7NexHApq3 YlJYxKEdI compare with XJ6PG8CB6GgkZYn5XkWVoObDRUYaDY53r5VMGZ QgO52mKrr0u6ENEjlbOpfStkXEf6VgAlQOrGKOEViYL3NhKj LV7toOdYJffMlEAT6Kh PeWC01bkhA9DnbsxPMeXy5Y8fU
XuSmwiGvyDv 5QbQsc5Ae4BSUueh5g E5lz2Kwi XPlRvYxR6tqyIyhnkQ7Vl 7e2hI6CFGcdmzaNSDAaqECGW7u0V0aBuHBwef C5nIB MakXQ0xH7Ua9 RzCUAf3sVopCCn2E
Problem 163
At 27IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM two moles of an ideal mono atomic gas occupies a volume V. The gas expands adiabatically to a volume 2V. Find:
(i) The final temperature of the gas
(ii)The change in its internal energy
(iii) The work done by the gas during the process.
Given that R = 8.31 J R2eoO0g1CwPoy0jMKmDITAu 97t Caj04EI5YY5P8 OsVHs1GffYZMwP5FeKJoPARr40o9d0IkE1F0nzzrOyfdaDqVxk0knNJYKqSLOFp C2knRBVAQSnFUOqVU45xI SUbCnU
Problem 164
A gas volume and at a pressure of 4 Image?w=77&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw is compressed adiabatically to a volume 0.5 . Find its new pressure. Compare it with the pressure obtained if compression were isothermal. Calculate the work done in each process. Image?w=117&h=51&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Problem 165
  1. Explain what is meant by temperature gradient.
  2. An ideally lagged compound bar 25 cm long consists of a copper bar 15 cm long joined to an aluminum bar 10 cm long and of equal cross-sectional area. The free end of the copper is maintained at 100IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVMand the free end of the aluminium at 0IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. Calculate the temperature gradient in each bar when steady state conditions have been reached. (Thermal conductivity of copper =
390 W MjGbqtPkbxV397IxxJ7NzIZmWC5lWO2cbCrBrBVoIcZYMDuPjlhQtLDmgucG4izrmWW3nJ0e8cJ 86bVmj1lBCWnPrWIawHDgxXV GhdxBH5HpRJj7GgUQjHkCejMQ 9RSsTfWQ. Thermal conductivity of aluminium = 210 W 6Zwnj 9s1oIrzsIMnfNuaM6s8UlrZGgKDRlnDf7UmE3vFhwmE7Nzy9 WUYqK MxsWUElyvwWeqNjvN9 L5bzFJjxNTCQa4FJriK5KUG2oZx1toIL2os53T0AJMxaaA9LBrseQ6A.)
Problem 166
  1. If a copper kettle has a base of thickness 2.0mm and area3.0 x Uc7SaPD4gaPbTY1axRIpHiBgLZHzUfHlNjDXLgDUKVDQPlkW8qDileGI8C9F1py84YEIOY FxhKZ17I5mPSoxnakfnZFfzFM7V9aQLoH2IpI8HKtHFds2 P A8h69LEcZyobHi4, estimate the steady difference in temperature between inner and outer surfaces of the base which must be maintained to enable enough heat to through so that the temperature of 1.00 kg of water rises at the rate of 0.25 . Assume that there are no heat losses, the thermal conductivity of copper = Image?w=128&h=49&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
3.8 W and the specific heat capacity of water = 4.2 Image?w=126&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw.
  1. After reaching the temperature of 373 K the water in (a) above is allowed to boil under the same conditions for 120 seconds and the mass of water remaining in the kettle is 0.948 kg. Deduce a value for the specific latent heat of vaporization of water ( neglecting condensation of the steam in the kettle
Problem 167
A cubical container full of hot water at a temperature of 90 is completely lagged with an insulating material of thermal conductivity 6.4 W . The edges of the container are 1.0m. Estimate the rate of flow of heat through the lagging if the external temperature of the lagging is 40IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. Mention any assumptions you make in deriving your result. Image?w=129&h=48&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Problem 168
A thin-walled hot-water tank having a total surface area 5MMuisXeNvpzTl7ySWHv1Q ADqfA0MsYUDFh5x9L6V8V0uMg6tD5jmkwPLf4Po4bLhHilrbFdRzp5izTzD439OGdAJGB72f3lxp1YuXsqKzAUG2ibkB78KcoflOdftrlJwuUHCd8, contains 0.8 RhDLl7auLl5LVD4h0XqJh2CXnhymO0ILTM9ZK4d6TE4oFSDitZuazTwmSoX3jS0nM0HuSxYm Q9 NIS2da1JCZhPtQaVAxwM4X6 3Ok7zFx25E1xIWBGeR4qBDiNuMwctKSrXno of water at a temperature of 350 K. It is lagged with a 50mm thick layer of material of thermal conductivity 4
Image?w=135&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw. The temperature of the outside surface of the lagging is 290 K. What
electrical power must be supplied to an immersion heater to maintain the temperature of the water at 350 K? Assume the thickness of the copper walls of the tank to be negligible) What is the justification for the assumption that the thickness of the copper walls of the tank may be neglected? (Thermal conductivity of copper = 400 W Pk54X8VVZx0IzgRnQKZJobvuZQVs Mon IzmI8CMwXUZ OfNxCoC2YzVx5ShEUlqKT6 U7Al5nqh8gX0Zh43REd2os3cjlwf LmStk5DmKGBlhnF 6oNIA BvsUkTvS Oh9VLpU.
If the heater were switched off, how long would it take for the temperature of the hot water to fall 1 K?
(Density of water W00nYc5igJT P65qTN GiLW2oe47c77669ZyHeZQGV5bc8eXDn9B YiHz8SAIciVLCCCntO6i88SsdTpo KFr7mYMnsJ3vDv ZXADONkYq03nWTgn9nTIQGVqZNpwQUWbqoMZY1000 kgEX1IY00IZqZ5G0eDW6rZ9Wa9qPk KU1hHl2u91kirpAZGoaJ4aY9jf2X0Suq0o1 VsxyvggYS58qTWyXMBgaojnoad2LQfWV5fGrRdQfZZUePRN0OGHtq5VU1HQjf9IXs9pQD8c specific heat capacity of water = 4170 J GqpME OSuVyimmULx3tbId3YyD5EqMW TRTUPmwcg5zr36cBBQNb10sUbBKzBA8Q GM6SXz4VTcJHjozFKCsOABd2Q0g3FkCAMJavZlRP5ZQXwKf1FKNHVfGiSj2WkAVEmHWHqc.)
Problem 169
  1. Sketch graphs to illustrate the temperature distribution along a metal bar heated to one end when the bar is (a) lagged, and (b) unlagged. In each case assume the temperature equilibrium has been reached. Explain the difference between the two graphs.
  2. A window pane consists of a sheet of glass of area 2.0 and thickness 5.0mm. if the surface temperatures are maintained at 0IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and 20 , calculate the rate of flow of heat through the pane assuming a steady state is maintained. The window is now double glazed by adding a similar sheet of glass so that a layer of air 10mm thick is trapped between the two panes. Assuming that the air is still calculate the ratio of the rate of flow of heat through the window in the first case to that in the second. Image?w=42&h=49&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
(Conductivity of glass = 0.80 W Pk54X8VVZx0IzgRnQKZJobvuZQVs Mon IzmI8CMwXUZ OfNxCoC2YzVx5ShEUlqKT6 U7Al5nqh8gX0Zh43REd2os3cjlwf LmStk5DmKGBlhnF 6oNIA BvsUkTvS Oh9VLpU, conductivity of air = 0.025 W Pk54X8VVZx0IzgRnQKZJobvuZQVs Mon IzmI8CMwXUZ OfNxCoC2YzVx5ShEUlqKT6 U7Al5nqh8gX0Zh43REd2os3cjlwf LmStk5DmKGBlhnF 6oNIA BvsUkTvS Oh9VLpU.)
Problem 170
An iron pan containing water boiling steadily at 100IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM stands on a hot-plate and heat conducted through the base of the pan evaporates 0.090 kg of water per minute. If the base of the pan has an area of 0.04MMuisXeNvpzTl7ySWHv1Q ADqfA0MsYUDFh5x9L6V8V0uMg6tD5jmkwPLf4Po4bLhHilrbFdRzp5izTzD439OGdAJGB72f3lxp1YuXsqKzAUG2ibkB78KcoflOdftrlJwuUHCd8 and a uniform thickness of 2.0 Image?w=50&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcwm, calculate the surface temperature of the pan.
(Thermal conductivity of iron = 66 W Pk54X8VVZx0IzgRnQKZJobvuZQVs Mon IzmI8CMwXUZ OfNxCoC2YzVx5ShEUlqKT6 U7Al5nqh8gX0Zh43REd2os3cjlwf LmStk5DmKGBlhnF 6oNIA BvsUkTvS Oh9VLpU. Specific latent heat of vaporization of water at
100Image?w=138&h=27&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw)
Problem 171
    1. A sheet a glass has an area of 2.0 and a thickness 8.0 x YbDroQ59GHVPI5UcG BPhoRvEoqnLRBavOU0FvdBHoTnIpWE OBNMvw5zevO MPLoJ UwK MJQ MIJ5bp5Brhkz3cN57RgBIamqS7NzZZ53OXwSbWSschKce04A5MGhEP ETu8Am. The glass has a thermal conductivity of 0.80 W . Calculate the rate of heat transfer through the glass when there is a temperature difference of 20 K between its faces. Image?w=58&h=49&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
    2. A room in a house is heated to a temperature 20 K above that outside. The room has
2 MMuisXeNvpzTl7ySWHv1Q ADqfA0MsYUDFh5x9L6V8V0uMg6tD5jmkwPLf4Po4bLhHilrbFdRzp5izTzD439OGdAJGB72f3lxp1YuXsqKzAUG2ibkB78KcoflOdftrlJwuUHCd8 of windows of glass similar to the type used in (a) above. Suggest why the rate of heat transfer through glass is much less than the value calculated above.
Problem 172
  1. Explain why two sheets of similar glass each 4mm thick separated by a 10mm layer of air. Assuming the thermal conductivity of glass to be 50 times greater than that of air calculate the ratio.
  1. A double-glazed window consists of two panes of glass each 4mm thick separated by a 10mm layer of air. Assuming the thermal conductivity of glass to be 50 times greater than that of air calculate the ratio.
(i) Temperature gradient in the glass to temperature gradient in the air gap. (ii)Temperature difference across one pane of the glass to temperature difference across the air gap.
Problem 173
  1. Outline an experiment to measure the thermal conductivity of a solid which is a poor conductor, showing how the result is calculated from the measurements.
  2. Calculate the theoretical percentage change in heat loose by conduction achieved by replacing a single glass window by a double window consisting of
    two sheets of glass separated by 10mm of air.
Problem 174
The silica cylinder of a radiant wall heater is 0.6m long and has a radius of 5mm. If it is rated at 1.5 kW estimates its temperature when operating. State two assumptions you have made in making your estimate.
(The Stefan constant, Image?w=171&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw = 6 ).
Problem 175
  1. Explain what is meant by black body radiation
  2. A blackened metal sphere of diameter 10mm is placed at the focus of a concave mirror of diameter 0.5m directed towards the sun. If the solar power incident on the mirror is 1600 W P JNc2M1nVXAxxrMl9UbLscSfyIshS24QDD 6CZyfSK1BFopQzuM9o0rgarE10fIavll3kSUguZNe2pWavphHNOONMQK4nNH RZyxZhDRkYl0XRrCuHMdu3teBZnN2a5PJPw 0. Calculate the maximum temperature in which the sphere can attain. State the assumptions you have estimated.
(The Stefan‘s constant, = 6 Image?w=132&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw).
Problem 176
If the mean equilibrium temperature of the Earth‘s surface is T and the total rate of energy emission by the sun is E Show that
Image?w=82&h=31&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw =
Where Rcvh0gEwe8is4XJEJeKNslGjiKtaF2NyXlILuP3ZxIq5nYEn1JBiLYbTHOcnM WQ2MGJrm6NUdIp0rkFKw6qSQtQ1s7BahpHydmNvGr7LKxl2IAxRdrZCnM VYaNxTmbH37BTTE is the Stephan constant and R is the radius of the Earth‘s orbit around the sun.
(Assume that the Earth behaves like a black body)
Problem 177
An unlagged thin-walled copper pipe of diameter 2.0 cm carries water at a temperature of 40 K above that the surrounding air. Estimate the power loss per unit length of the pipe if the temperature of the surroundings is 300K and the Stefan constant, Rcvh0gEwe8is4XJEJeKNslGjiKtaF2NyXlILuP3ZxIq5nYEn1JBiLYbTHOcnM WQ2MGJrm6NUdIp0rkFKw6qSQtQ1s7BahpHydmNvGr7LKxl2IAxRdrZCnM VYaNxTmbH37BTTE, is 5.67 Image?w=131&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw).
State two important assumptions you have made.
Problem 178
The solar radiation falling normally on the surface of the Earth has an intensity 1.40 k WP JNc2M1nVXAxxrMl9UbLscSfyIshS24QDD 6CZyfSK1BFopQzuM9o0rgarE10fIavll3kSUguZNe2pWavphHNOONMQK4nNH RZyxZhDRkYl0XRrCuHMdu3teBZnN2a5PJPw 0. If this radiation fell normally on one side of a thin, freely suspended blackened metal plate and the temperature of the surroundings was 300 K, calculate the equilibrium temperature of the plate. Assume that all heat interchange is by radiation.
(The Stefan constant = 5.67 Image?w=132&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw).
Problem 179
A steel rod has length 1.5m and radius 1 cm. One end of the rod is maintained at 100IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and the other end is at 0IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. Find the quantity of heat conducted through the rod in 2 minutes. The thermal conductivity of steel is 50.4 W/m K.
Problem 180
A glass window pane of a room has dimensions 2m L3vnb7tAqB 5Qi7Vfr37DHI 6cKabv3WRy7CfKIeXpR4psodrJr G4NbQ2u OybWIMpflaDusEJgoeAu QjWla2u4RFUe WruHSLMUOQ2roIEg1 Ax5 LIgoaYpJkMFowFQXCM 0.5 m x 0.002m. The temperature on its two sides are 300 K and 295 K respectively. Find the quantity of heat conducted out of the room in 10 minutes if the room has two windows, each having two such panes.
2UODY1DyJ04Lmx TTroaZGxvXbzMMZvQOvnwvU7YSIufKW Rp 02Ov6f7i8s5ozNvqBoA3fA11xSzsRgOQY6FpgnlsvrUtjW1rYaPQ3LuHryjh7vHQAHEe2wOX5fOUDtMUMYhM
Problem 181
In Searle‘s method. A metal rod of length 50cm and area of cross-section 8 LsZ1UKe1Xeni38mWj52gY7HJHjPXJmphoxANTOkj79RHZh7uTPm7tm1aqdPKOeWBzKJ16OHBG6YrA3oEo2tQmy EbAkdvBZJ06MwnCR FmnTzd2lQDu7eOu8g7cQBoxmN29f1qc is used. The flow of water through the tube is adjusted at 20 grams per minute. The stead temperature of 65IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and 55IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM respectively are shown by the two thermometers instead in the rod. The separation between the thermometers is 4 cm. The out flowing water shows a rise of 6IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. Find the thermal conductivity of the metal.
Problem 182
In Searle‘s experiment for the measurement of thermal conductivity of a metal, a road having a cross-sectional area of 10LsZ1UKe1Xeni38mWj52gY7HJHjPXJmphoxANTOkj79RHZh7uTPm7tm1aqdPKOeWBzKJ16OHBG6YrA3oEo2tQmy EbAkdvBZJ06MwnCR FmnTzd2lQDu7eOu8g7cQBoxmN29f1qc is used. The flow of water through the cooling tube is adjusted at 150gm/minute. When a steady state is reached, two thermometers, inserted in the road at a distance of 5cm from each other, record temperature of 60 and 50 respectively. If the rise in temperature of the water flowing through the cooling tube is 5 , find the thermal conductivity of metal. Image?w=76&h=49&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Problem 183
The temperature inside an air-conditioned room is maintained at 20IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM when the outside temperature is 30 . Calculate the quantity of heat conducted per minute through a glass window pane of area 0.25 and thickness 5mm if the thermal conductivity of glass is 0.84 W/mK. Image?w=23&h=49&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Problem 184
The temperature inside the room is 15IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and that of outside is 5IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. How much heat will be lost by conduction per hour through one square meter of the wall if its thickness is 25cm [K for the material of the wall = 2.5 w/mK]
Problem 185
Calculate the amount of heat conducted per minute through a glass window pane of length 50cm, breadth 20cm and thickness 0.5 cm, if there is a steady temperature difference of 10IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM on its two sides (Thermal conductivity of glass = 0.002 CGS units)
Problem 186
One end of a copper rod 20 cm long and 5 cm in diameter is maintained at 50IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM while the other end is kept at a constant temperature of 20IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. Calculate the quantity of heat conducted through the rod in 10 seconds if the thermal conductivity of copper is 0.92 CGS units
Problem 187
A large glass window has an area of 10 and thickness of 3mm. If the temperature in side and outside the room is 20IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and -10 respectively, calculate the quantity of heat flowing per second through the window. Thermal conductivity of glass = 1.5 Image?w=51&h=26&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw MKS units) Image?w=73&h=49&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Problem 188
In Searle‘s method, rod of length 30cm and cross-sectional area 5 is used and flow of water is adjusted at 60 grams per minute. Steady temperature
of 60 and 50 respectively are shown by two thermometers inserted in the rod 8cm apart. If the water coming out of the spiral shows 5IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM rise in temperature, calculate the thermal conductivity of the metal. Image?w=76&h=49&rev=1&ac=1&parent=1LROdijXKcU8Ys2KKp6YZtwhvOKDJrPcw
Problem 189
The thermal conductivity of brass is 0.26 cal/s cmIF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. In Searle‘s experiment a brass rod having a cross-sectional area of 10 LsZ1UKe1Xeni38mWj52gY7HJHjPXJmphoxANTOkj79RHZh7uTPm7tm1aqdPKOeWBzKJ16OHBG6YrA3oEo2tQmy EbAkdvBZJ06MwnCR FmnTzd2lQDu7eOu8g7cQBoxmN29f1qc is used. When the steady state is reached, the temperature recorded by the two thermometers, inserted in the rod at a distance of 4 cm from each other, differ by 5IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. If the rate of flow of water through the cooling tube is 0.5 gm/s. find the rise in temperature of water.
Problem190
A hollow cube of metal having mean length 10cm and thickness 0.25cm is filled with ice at 0IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM and is surrounded by water at 80IF HWHAVFtm9k69B037oaVVz6duhn2maUBZp IAwS1REgb85J Wnjm4N UHu7HUwI2nelhb2A V6 4xu0 X6Q3XFyEKkkfPYShRhsZSShmpskOIXZJh FOy0nEMwH80gr4uMKVM. How much ice will melt in ten minutes?

Latent heat of ice = 80 kCal/g.




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