Area of a triangle Questions
1. The sides of a triangle are in the ratio 3:5:6. If its perimeter is 56 cm, use the Heroes formula to find its area (4mks)
2. The figure below is a triangle XYZ. ZY = 13.4cm, XY = 5cm and angle xyz = 57.7o

Calculate
- Length XZ. (3mks)
- Angle XZY. (2 mks)
- If a perpendicular is dropped from point X to cut ZY at M, Find the ratio MY:ZM. (3 mks)
- Find the area of triangle XYZ. (2 mks)
3. The figure below represents a triangular plot ABC. The lengths of AB = 50m, AC = 80m



and angle BAC =30o
(a) Find the length of BC to 2 s.f
(b) Find the area of the plot in hectares
(c) The plot is fenced using 4 strands of barbed wire. The length of one roll of barbed
wire is 600m and it costs shs.4000. Calculate;
(i) The length of fencing wire required
(ii) The number of complete rolls to be bought
(iii) The cost of the rolls
Area of a triangle Answers
1. a) BC2 = 502 + 802 – 2 x 50 x 80 cos30
= 2500 + 6400 – 6928.20 = 1971.8
BC =√ 1971.8
= 44.40m
= 44m
b) Area of the plot
= ½ x 50 x 80 x sin30 = 1000m2
= (1000) ha
10000
= 0.01ha
c) i) Length of wire required
= (50 + 80 + 44) x 4 = 696m
ii) Complete rolls to be bought = 2
iii) Cost ( 2 x 4000) = Shs.8000

