STATISTICS

Definition

Statistics is a branch of mathematics dealing with the study of methods of collecting, organizing, analyzing, presenting, and interpreting numerical data to reach conclusions.

Frequency distribution

Frequency distribution is the number of times each data point occurs.

Example 1

1. Make a frequency table from the following data of ages of 10 students:

14, 15, 16, 14, 17, 15, 16, 13,

Frequency table example

2. In a mathematics test, the following marks were obtained:

48, 47, 42, 67, 73, 50, 76, 47, 44, 44, 57, 58, 54, 45, 58, 56, 66, 67, 45, 43, 71, 48, 64, 52, 42, 54, 62, 32, 49, 34, 35, 46, 89, 37, 47, 54, 45, 60, 64, 44.

If the class size of the class interval is 8, group the marks starting with the interval 32-39 and draw the frequency distribution table.

Solution

MarkFrequency
88-951
80-870
72-792
64-716
56-636
48-558
40-4713
32-394
n=40

Example

From the example above, find the class mark of the class intervals 88–95 and 80–87.

Class mark: class mark formula and class mark formula

= 91.5 and 83.5

Class limits example in class interval 88 – 95

88 is the class lower limit.

95 is the class upper limit.

Class real limits

Class lower real limit is the number obtained by subtracting 0.5 from a class lower limit, e.g., 88 – 0.5 = 87.5.

Class upper real limit is obtained by adding 0.5 to the upper class limit, e.g., 95 + 0.5 = 95.5.

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Class size

Class size is the value obtained by the difference between the upper real limit and the lower real limit.

Example

From class interval 88-95 and 31-35, find the class size.

Solution:

Lower class real limit = 88 – 0.5 = 87.5

Upper class real limit = 95 + 0.5 = 95.5

Class size = 95.5 – 87.5 = 8

Lower class real limit = 31 – 0.5 = 30.5

Upper class real limit = 35 + 0.5 = 35.5

Class size = 35.5 – 30.5 = 5

Exercise 1:

1. In a biology class test, the following marks were obtained:

54, 54, 40, 55, 54, 43, 73, 34, 75, 47, 35, 45, 73, 46, 31, 43, 47, 35, 35, 60, 67, 51, 44, 48, 55, 45, 50, 37, 51, 36

By grouping the marks in class intervals 20-29, 30-39, 40-49, etc., construct the frequency distribution table.

Solution:

MarksFrequency (f)
20-290
30-397
40-4910
50-598
60-692
70-793
N = 30

2. The following data represent the masses of 10 people in kg. Construct the frequency distribution table for these people:

30, 25, 35, 28, 38, 40, 25, 25, 40, 24

Mass frequency table

3. The following is a set of marks on a geography examination presenting the frequency distribution table with class intervals, real limits, class marks, and interval size starting with the interval 8-15 at the bottom.

Solution:

Class intervalReal limitsClass marksIntervalFrequency (f)
88-9587.5-95.591.583
80-8779-87.583.583
72-7971.5-79.575.586
64-7163.5-71.567.583
56-6355.5-63.559.586
48-5547.5-55.551.584
40-4739.5-47.543.587
32-3931.5-39.535.584
24-3123.5-31.527.588
n=50

4. Fill in the blank columns:

Distribution of 100 math examination scores:

Class intervalReal limitClass marksIntervalFrequency (f)
95-9994.5-99.59753
90-9489.5-94.59257
85-8984.5-89.58759
80-8479.5-84.582513
75-7974.5-79.577520
70-7469.5-74.572523
65-6964.5-69.567517
60-6459.5-64.56258
N=100

Note: Class real limits are also known as class boundaries.

GRAPHS OF FREQUENCY DISTRIBUTIONS:

HISTOGRAMS

Histograms of frequency distribution are rectangular figures plotted with class marks against frequency. The width of the histogram equals the class size.

Example:

1. Draw a histogram of 100 mathematics examination scores in the table below:

Class intervalClass markFrequency
95-99973
90-94927
85-89879
80-848213
75-797720
70-747223
65-696717
60-64628

Histogram example

2. Use the following distribution table below to draw a histogram:

AgeFrequency
131
144
152
162
171
N=40

Histogram solution

FREQUENCY POLYGON

A frequency polygon is the line graph of class frequency plotted against class marks.

Steps:

  1. Add one interval below the lowest interval and one above the highest interval and assign them zero frequency.
  2. Plot points and join them by straight lines.

Example:

1. Draw a frequency polygon from the following data.

Class intervalClass markFrequency
100-1041020
95-99973
90-94927

Frequency polygon example

EXERCISE

1. The following table shows female deaths between 0 and 34 years to the nearest numbers. Represent this information by:

  • A) Histogram
  • B) Frequency polygon

Expected death of female per 100 women:

AgesF (death risks)Age
0-43402
5-9957
10-145512
15-196017
20-249522
25-2911027
30-3412032
35-3912537
N=1000

Solution:

A) Histogram

Histogram solution

B) Frequency polygon

Frequency polygon solution

2. Table below shows the distribution of marks obtained by 110 students in two different monthly tests. Draw the frequency polygon on the same chart.

MarksFrequencyMarksFrequency
21-30421-302
31-40731-4012
41-501041-5015
51-60551-604
61-70361-703
71-80171-804
N=40N=40

Frequency polygon example

3. Platforms in each square metre of a lawn were counted and recorded as follows. Draw an ogive for the platforms.

No. of platformsFrequency (f)Cumulative Frequency
01010
1818
2725
3530
4434
5539
N=37

Ogive example

REVISION EXERCISE

1. The ages of the 22 players in a football match were recorded as follows:

17, 18, 15, 16, 16, 16, 18, 15, 18, 15, 15, 18, 18, 15, 16, 17, 15, 16, 17, 15, 15, 16, 15, 18, 15

Express the data in a frequency table.

Solution:

AgesFrequency
1510
165
172
185
N=22

2. The examination marks of 45 students are:

65, 58, 71, 62, 64, 35, 72, 32, 64, 46, 59, 82, 73, 76, 64, 63, 75, 71, 61, 36, 64, 80, 61, 64, 76, 64, 60, 68, 48, 35, 92, 73, 46, 24, 35, 43, 30, 50, 70, 40, 46, 64, 24, 28

A) Make a frequency distribution using class intervals 21-30, 31-40, 41-50, etc.

Solution:

Class intervalFrequency
21-304
31-406
41-506
51-604
61-7014
71-809
81-902
n=45

B) Draw cumulative frequency curve.

Solution:

Cumulative frequency curve

3. Two plots A and B were treated with different fertilizers. The frequency number of potatoes on samples of 100 plants on each plot are shown below:

No. of potatoesPlot APlot B
3117
82628
132830
182714
2353
2886
3332

Draw a histogram for plot B.

Histogram plot B

4. In a certain examination the results were as follows:

  • 3 students got marks between 0 and 10
  • 5 students got marks between 10 and 15
  • 6 students got marks between 20 and 40
  • 4 students got marks between 30 and 40
  • 2 students got marks between 40 and 50

Construct a histogram.

Histogram example

5. Final scores of history examination were recorded as shown in the table below:

ScoreFrequencyClass mark
50-54152
55-57257
60-641162
65-691067
70-741372
75-791277
80-842182
85-89687
90-94992
95-99497

A) What is the size of class intervals?

Solution:

5 is the size of class intervals.

B) Draw a histogram to represent the scores.

Histogram scores




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