TRANSFORMATION IN THE PLANE
Transformation in the plane is a mapping which shifts an object from one position to another within the same plane.
Examples of transformations in the xy plane are
i. Reflection
ii. Rotation
iii. Enlargement
iv. Translation

REFLECTION
-The action or process of sending back light, heat or sound from a surface.

ISOMETRIC MAPPING
-Is a transformation which the object size is maintained.
-Reflection is an example of isometric mapping.

Reflection in the line included an angle (α) passing through the origin.
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UQT2ncjahKfUPIaqR2tmU56PZHsQNpPHiJPBGqTu0BHW3h XVnbRKwSRvE6Tp5GM 8uTETysRgUSqx5ET8lICgE9kc2pykG3b6xgZUfyeSkrDqCZQc6PlS2Vct RY46VrgqurW0 inclined at B with the coordinates being (X, Y)
UQT2ncjahKfUPIaqR2tmU56PZHsQNpPHiJPBGqTu0BHW3h XVnbRKwSRvE6Tp5GM 8uTETysRgUSqx5ET8lICgE9kc2pykG3b6xgZUfyeSkrDqCZQc6PlS2Vct RY46VrgqurW0 is the image of UQT2ncjahKfUPIaqR2tmU56PZHsQNpPHiJPBGqTu0BHW3h XVnbRKwSRvE6Tp5GM 8uTETysRgUSqx5ET8lICgE9kc2pykG3b6xgZUfyeSkrDqCZQc6PlS2Vct RY46VrgqurW0 under reflection is GoGmh XVuS8pvek83KMAOZnCEenWoLLLhIN8oPZwd79fEMxCQZZAbUdZooWFkXE0eztkOBra5ZR5XsfaCx DTE3XLNGpeEZKlmODOXVMNcslsBvTvn2wwU4s2zo9 LB7Z R Mi4
PP is perpendicular to OS (GoGmh XVuS8pvek83KMAOZnCEenWoLLLhIN8oPZwd79fEMxCQZZAbUdZooWFkXE0eztkOBra5ZR5XsfaCx DTE3XLNGpeEZKlmODOXVMNcslsBvTvn2wwU4s2zo9 LB7Z R Mi4 is the line of reflection)
POS= α GOF2bTfKfIfeU0L8uvpCxRfG5BzpbnkDO0AY5xzlCq4ZXf3TAsJkuapWhfwj4SbzZjf84NyAtcxYhclmPdpvopBf6x C7Ip0afEwjEIKEfqDPO 913HtvYJO2qDYYdL48 MfjwU β

Δ OPQ is right angled a
t Q

Hence X = OP cos B……(i)
Y = OP sin B
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Coordinates of R are ( X1,0)
OR= X 1
RP1=Y1
Δ OP1R is right angled at R
P1OS= POS= α-β
Angle P1OR = α – β + α – β + β = 2α – β
Cos (2α-β)= X1
OP1
X1= OP1cos (2α-β)….. (iii)

Y1 = sin (2α-β)
OP1
Y1=OP1sin (2α-β)……(iv)
Cos (A+B) = cos A cos B – sin A sin B
Sin(A+B) = sin A cos B+ sin B cos A
X1 = OP1 cos 2α cosβ + OP sin 2α cos β…. (iii)
Y1= OP sin 2α cos β – OP1 sin B cos 2α
X1= OP cos 2α cos β+ OP sin 2α sin β
Y1= OPsin2αcos β – Op sinβ cos 2α
X1 = OP cos β cos2α + OP sin β sin 2α
Y1= OP cos βsin 2α – OP sin β cos 2α
X1 = X cos 2α + Y sin 2α …..( i)
Y1 = X sin 2α – Y cos 2 α …..(ii)
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Exercise
1. Find the image of the point A (1, 2) after a reflection in the Y= X plane.
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Solution;
Y= X
1Yy2fKR3eT BmILaLrYEzrv QFAmxhSV3GgAGPWxixJNQ12NFpvbE9F6hlPY0oaHmcKQl27PzMtUKBn BCF4LEb9Vt1FEMrlwAKjFoAyp91Il5E Vhnr9O0iwJo99vTzQNM8aCY = 1
Tan α =1Yy2fKR3eT BmILaLrYEzrv QFAmxhSV3GgAGPWxixJNQ12NFpvbE9F6hlPY0oaHmcKQl27PzMtUKBn BCF4LEb9Vt1FEMrlwAKjFoAyp91Il5E Vhnr9O0iwJo99vTzQNM8aCY = 1
α= 900
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