MATRICES


Operations on matrices
A matrix represents another way of writing information. Here the information is written as rectangular array. For example two students Juma and Anna sit a math Exam and an English Exam. Juma scores 92% and 85%, while Anna scores 66% and 86%. This can be written as.
WT1f9Ch5k8zCHte2QYWnXjsFtUHJHaN MJFkixCch0DGAOLIor2KenW G6nRDKzKwNvVQFua8m3 A6hXkTKxUB5X TkIDrldahniyqMEq8aWmXcHOT1YSUsz2Kbg5vakkkdzkNk


A size of a matrix is known as its order and is denoted by the number of rows times the number of columns. Therefore the order of above matrix is JIWd FwdN8cvSU3Be OYHQ874 Afj28fpfx3yZeHVgTKuILvLRty5Sx6kzxxATuaV9VRQQVvG7n1u0cXhaBwROPcWfu4vfxx1yVFA9VZQXEYBn Ti9nfgHvXzAmlqz93Lh0wdq4 each of the numbers in the matrix is called an element.

Types of matrix
(i) Row matrix. This is a matrix having only one row. Thus M4tRnW6dRS FJbF5rlVI6UPYZ4UE3dMzwCCFT1oUbqIhgRVAfYNWGdtbNPAErBJ02k ZqHFmhm2NlxdMrvV8LyLZwqxiI5Fw00kVeGCwcFYHd4ZEu9a8qfgLW4EQuGiL59153 4 is a row matrix.
(ii) Column matrix. This is a matrix having only one column. Thus HdMu1gqy LiCeY7MroDmiRFHNXzeombmqoS3htVdodnGiPIjBK1rCcXQmOplAFRthXehawYHR9QF1tidNg8fjQGnDPAqmaHuYVGMyS8x17UVchK9NNsqLwNUJcCsHkPlox3o2Lk is a column matrix.
(iii) Null matrix. This is a matrix with all its elements zero. Thus WgKrVrA2ruvvaT7hTCZwRMmGndA7AHkIMbc7 UKM4GHIz9Dc NcaOLaYUn39pDenqgv8qv MDCQHGYCsblDDZY1pR6Rq5Jj7B J PtZSm8zHK2MZgvnpiDzv DDbgdwkhJ74w4o is a null matrix or zero matrix.
(iv) Square matrix. This is a matrix having the same number of rows and column. Thus SX6Pc69Ikttgog3iT6UMDHdf1MQH DSuEym1qTYSywkMnBGcaZ7HKWLngCyNYqjWB6fLCeLPY32Gf0tAAmYoQHAbSqdQpYuA8oXTQR5BmPil20WVU88iWoEVFVOJ830Y1g5x1gw is a square matrix.
(v) Diagonal matrix. This is a square matrix in which all the elements are zero except the diagonal elements. Thus VRV HwQrD3u34zAzA2imZKiu2dqudfvCDTB7Df4SUCCHTAKhx7ASgMHw39oeRu7QNPGCosdgwTNgL5AIEUvozB6H3QAVRnv AIapap29m4GXwc IGg Q5vGFHuF27j35Qzs1 DQ is a diagonal matrix.
Note that: The diagonal in a matrix always runs from up left to lower right.

(vi) Unit matrix of identity matrix. This is a diagonal or square matrix in which the diagonal elements equal to 1. An identity matrix is usually denoted by the symbol I. Thus
I =  0dUbWw9g0Jr DvbRrb090QT7wDEPmuk1YRKRmZTfYEFfD3jdlXlAqw2p5ujC2eR HGqZSo3KISg L3FnwCxJwyfFp8J1ZUSYH4MSnagH2dNrMB6g5l8jh DiwvkKWv78hynjY0

(vii) Equal matrix. Two matrices are said to be equal if they are of the some order, responding elements are equal.
Uuk1kWtlsfqQPGWA8vjACTul4GIHXR S4ZL6kjcC0FuGon3UX1vlcExNSairDE7I0Acg8uVTqE1vX 0Jvh87ryMHR1 LQmT83T5mvIDAMX31Y9b5BS8CwKdWNndPPrNMTwblB0c
An m x n matrix (E.g. matrix A) is a rectangular array of m x n real (or complex numbers) arranged in M horizontal rows and n vertical columns.
A =WT1f9Ch5k8zCHte2QYWnXjsFtUHJHaN MJFkixCch0DGAOLIor2KenW G6nRDKzKwNvVQFua8m3 A6hXkTKxUB5X TkIDrldahniyqMEq8aWmXcHOT1YSUsz2Kbg5vakkkdzkNk
Example
1. The table below represents number of students in each stream in each form. Now write that information in matrix.
Form
I
II
III
IV
Stream J
36
38
30
41
Stream K
38
41
29
30
Stream L
29
50
35
42
J = JIWd FwdN8cvSU3Be OYHQ874 Afj28fpfx3yZeHVgTKuILvLRty5Sx6kzxxATuaV9VRQQVvG7n1u0cXhaBwROPcWfu4vfxx1yVFA9VZQXEYBn Ti9nfgHvXzAmlqz93Lh0wdq4

2. Give the order of the following matrices.
i.A = M4tRnW6dRS FJbF5rlVI6UPYZ4UE3dMzwCCFT1oUbqIhgRVAfYNWGdtbNPAErBJ02k ZqHFmhm2NlxdMrvV8LyLZwqxiI5Fw00kVeGCwcFYHd4ZEu9a8qfgLW4EQuGiL59153 4
has order 2×2

ii.B = HdMu1gqy LiCeY7MroDmiRFHNXzeombmqoS3htVdodnGiPIjBK1rCcXQmOplAFRthXehawYHR9QF1tidNg8fjQGnDPAqmaHuYVGMyS8x17UVchK9NNsqLwNUJcCsHkPlox3o2Lk

has order 2×3

iii. C = (P Q) has order 1×2
iv. D = WgKrVrA2ruvvaT7hTCZwRMmGndA7AHkIMbc7 UKM4GHIz9Dc NcaOLaYUn39pDenqgv8qv MDCQHGYCsblDDZY1pR6Rq5Jj7B J PtZSm8zHK2MZgvnpiDzv DDbgdwkhJ74w4o

has order 3×1


SPECIAL MATRICES
Is the matrix having all elements zero ( zero matrix)
Z = SX6Pc69Ikttgog3iT6UMDHdf1MQH DSuEym1qTYSywkMnBGcaZ7HKWLngCyNYqjWB6fLCeLPY32Gf0tAAmYoQHAbSqdQpYuA8oXTQR5BmPil20WVU88iWoEVFVOJ830Y1g5x1gw


IDENTITY MATRIX: Is the square matrix whose elements is the leading diagonal are everywhere 1 and 0 elsewhere.

I = VRV HwQrD3u34zAzA2imZKiu2dqudfvCDTB7Df4SUCCHTAKhx7ASgMHw39oeRu7QNPGCosdgwTNgL5AIEUvozB6H3QAVRnv AIapap29m4GXwc IGg Q5vGFHuF27j35Qzs1 DQ .

=  0dUbWw9g0Jr DvbRrb090QT7wDEPmuk1YRKRmZTfYEFfD3jdlXlAqw2p5ujC2eR HGqZSo3KISg L3FnwCxJwyfFp8J1ZUSYH4MSnagH2dNrMB6g5l8jh DiwvkKWv78hynjY0
Identity matrix

ADDITION OF MATRICES

Matrix addition is performed by adding corresponding elements.
for example
4wVoYGiyr ZFfefamP7pEaiIiWsGZVhBFL9gIyIsRkhB2SX A2ES1ZhKy2Au5nhdR53MiV3sffr8UyOb 9duy7T3BiLI1NuZgGalf2OpUNGYsFGk JdMzY0oZh5L45Etmdn8HdQ
Example
1. Given matrices A = (1 2 3) and B = ( 4 5 6)

Find
i. A + B
ii. B + A

Solution
i. A + B = ( 1 2 3) + ( 4 5 6)
= ( 1+4 2+5 3+6)
= ( 5 7 9)

ii. B + A = ( 4 5 6 ) + ( 1 2 3 )
= ( 4+1 5+2 6+3)
= (5 7 9)

2. If A = ActTr4Bs4swXJnCdaHAUGFrSorYe9l3pwy7MiaPLfOww5NlraQHQZkjrJ083WGyj KNy 7vCLY0gll5859sJaUMhd3OVqKYWB SPDBjbwnHw 0ebWeIbFAMhIztDNkx7 JsEpM and B = TvabpkmQVnk6MKJml21eJSUdADFCw17QetMjDn1RNZknuAEsG3RlCCmZ58kh AZcbNowNQeMBC2Eqr PwL RC7t2PIfY5grcfnjOIGBbnkLQ1f4si1gDScnhrZTQleijHdtEIG0

Then, find A + B
A + B = ZXJCe7c8nsNsmPcgGMxnixOAwy3kXabMUGIEIy8MP Md7ecFtO1kMmdmPAVTOd9Qqa80GvhCQ65q 0XvvNviE FFWDLwDympAedNoYbZDIokyDWXmrE1Xc7vQ NVbr7qx8znjMY+ V5dyOGdG 2ND4oGfr84XiDh5MHkAusffVrF6dkS S0zKVCwZcHO21lzm9e8x63jRH8yB83ZCxEQtdNSWvLVofpi6gekHKyemnJO7lVIYV FQRV77DGpcACyaPW8694NabOCCBnY
= FqCnUeTcf5LP7oKD8H 02Qdqc2Sln9BkoDzj5yEYA Z00AH4QAXv6l8wQkEe5EHyDq3W01pzuYvtt4nDRumyNZz94dE7WWNv SZ24brwEKGbVHMzB6ezxjTT517 Zv66D2m2QG4
ADDITIVE IDENTITY MATRIX
Consider any 2 x 2 matrix  7IIvCC7sZUh4dyUZoqrcDBrPJhRASo KSjfr B3AIIFAw8XUr3QPYKpLYXEd3Rqt0YGRJJQrT4k4E PstbLYPeH0LuW FnoRjuRliu3dzKu1Htwp6WCF0IVG5R4C2e6sRiuKWoN = , where a, b, c, and dare any real number. If N + Y = Y + N = N, then N

is the addictive identity matrix.
The 2 x 2 addictive identity matrix is YygvmTBZQOgVVo T2q6YitElLj7eoqF7IgUgcZkkXWoiHnxcwFvWMjnyM5FAjslhNuKnNosvIQ8LupC7LuIVFjPRcv6QOmOKmb26p9y6HFnVM2vxx2to1dB5HQetKLIB EEVc1E
Let matrix A = Gs9Q CjAQ6uazr 8PqGG4syTH BxmH 2HPn 7ZPqjQf0mIzlWFfT 8YLvQlzqguTU1KCA1dPRjRYvqkzTmia RutGjKz2UfuW5FLyk2mq5cYkuLhzy HX C 46n RNrOKaMzk
And Z = 4lvKbRrT ITEvQbj5j5pywi 0QxQKB5MX33l3K3xw8h7uDrPGLfs9BzMV61W0zjH YHmRsfmW4MDSp ShV 5mWqfGy1uDF OaMEptuAWer1P0IvZdjc PmSO9ukLqq8Jt RQAA

Then Z is an additive identity matrix.
i.e. A+Z = A and Z +A = A
4dLlwIj77i1KGBDU2ojas3SUIdYUYR68tE Kbr2bPo6HENj54YDCkdDILguAlV9 O 6t 7ydOs SWLdlTelRdRDxMAN9OP8DfAtCOkNstWeWfJhq319a4joqYkL44okmPm0CNpg
ADDITIVE INVERSE MATRIX
Consider any two matrices of the same order P and Q.
If P + Q = Q + P = R, then Q is called the additive inverse of P or P is called the additive inverse of Q.
i.e. Q = -P or P = -Q

Suppose,
9kriFZAI1wtaPoxHtnPzpSTFbLLxI68OoZqw9SaslGApXFrqV T6lDDW0k 4 SuVlHkB6M68OpIDwB3CZMcghTF3l YCJiMTglFIYOUL CkBzIUcSD4t8L3cjTykMhXMDtU73E
If P + Q = Z then,

Avocvee6z 1cIOvDoN9QygrcBjTUS3C1nmma VpJBwrPCT2w6M8XGK8BRH4Q0YYbjW3MvWAX7uxMzV5uDbPOfZlxPWGomXZKURAoC7iwFdntnbJJoeoT6 QUrLXKUyksY357SNE
= -P
Therefore the additive inverse of P is -P
Example
1. Find the additive inverse of
(a) B = ZFlm2mgzXW DM2 IEiuH C 7yjdl J0QuMiRFHrtrBt7mkBH UEuyq3ivk9397EHKUAhCvfaej1j7m595jxBUpHRxdq5UrTZaRCnWkL2tBVIf7vk2 FSYzlDMJ8f2Q6 KqWP80 (b) C= M0OMPgHNll Xo0CAB4hj5C09PociS4MykFnAOQjpSuHJUVdfLBvWLIn9mad3RZ20sCZ2u QyLcl LhyqWMU6x EL29Q Fj8WQPvoAiHqrN1GYxjHPlPwmhXy4Y8bUdNKzBFC5zI
Solution
U5ST95WevoUQUXJkDXJo5cLHqQLQ99 RcUfhIHqy QVKKYX7dRhDtNwaOVw UULBXK9a 8WUQBSrA V8L2nsop 8 LyjfpzupTFSDXdMMsrfJC0jdyy5MEgP 7iv I2otPSfclk
SUBTRACTION OF MATRICES
The process of subtracting a real number “f” from another real number g is the same as adding g to the additive inverse of f.
Thus f-g = f + (-g).

NOTE
When matrix P is subtracted from another matrix Q the result is the same as adding P to the additive inverse of Q.
i.e P- Q = P + (-Q).

EbrR82tZ8HdAlpsqpBP5w4dmIGCF18mt Xyv7lVjN1fJ0J2nBcXsIWzBOrPifnkBGs7sH6hBTV62cHK Bjrx7fwoLWZ5 WA0G0hwQ7HzegvO3i4bovy1di1XuYDBnDRB CYUrg


SCALAR MULTIPLICATION OF MATRICES
HVtn82vI2yVTwg1wILTZ UNNnOujRve NxFRwDA1qSs8aAG3GINJDH2jmbmy5gdgz0BdY2Afht6Zi63vd8c Q9ZMi16zxN4MhepwudAaX8FVimTcJKHKfPvogHF1ljUrpD5cF5s

Example If B = Xb49I9uzEzsdzbCbbbQXj1nuDQOhZKzWfol5droXhs8wmmEWX1 WbKp7lhIpMFrHNnFhR01HXlRXhlSkM K4KUXIa0esEUMlMz XRbZvRCpDX73JcMJdAtBGJViefojwGT5gsYs

i. Find 2B

Solution
2 NKeehuIGv72Pb6cINrea W ZjMqlAV WiGOGMi2jV1XC0xJxTvN4lDQXw1B089OMiGC BDMv9DeePIrS DiBlefUOZD1hPiccswX6DcNMQ5kouhq70i KOA5SO9psSE1MkWk5GQ= RaI9GrfCftHPxHOIoxMVhXn0lsK6wDsy7wDM59ylywGIen GB5uQqjfFPzi5vICkhoC2AChx9mfKw17 IAmmXOakPKRcOxUWGFMolRZZcnT7Mmt9 R3BqN6VNLQnPFsOVG1eVBw


ii. Find KlR8dZOWhO0hXSMntnGB0tFDxlS6mR0NbnJXTA2FALjUXqMnqAV8h RxCVISiyPg UmBLIkbxJwtqMNctSpKc Z96eHhdbvMWci9U NsaMzuaLfKrSd1FjY Zp7MTpYz45DFdVw B

Solution
AFvjW85m6tSqanhanb2yHRjRNnCSiw898qJBgRXRfyrjZSXLphjpPINmJ67HE5wAvJOsbPoEmCoJHJfkCPcXr X7LfbkDnyfqZR2ZAdfY5 03Fd02edDKAFxcc U6kQkQ4rOZYk= ZHu2sMesDNtlSFsqhkPUzpTCUhrTxQ9vlNwitDwK4s0q0ND47JWSREldcxDva0KbPRn29yusW4rkCJxu70HvTxOX0GTEfv2AfYiPxZbXY AaoCvZCv41YjbuF1RbTpKYrPzo1NA



Questions


1. Given;
A = AGCLd8kYdt938VaVPk3uMaWhaEJOlAb7VLVu6z4Wn3TyZuGDKKV9YrXt6PgGaEyboYL9CUhZhvtsZWWZR5ZfnoU9BmVyz7GIBht4xfWkLzX5 W3gf87a5jE9HpJqyO34lM5 UmI B = KOvs5eEoa5FI5hhNNJuMl QTaxFojsD GLzbOkfoktddNFMKO74UV5Szc54VIU9TvIn MvZWhq9RQuGbXd0Q7wNzayDCWFgzV4MJvJvEF3Z3fvXv EU4b3ZkZGmYkGGoWJwWWfEC = 3lBVFJXk5McwTnjdQD3XzwQKU0E0y27SDGosVBMlvk5mO3qa0IU3AWkWZyUGAlMzrCViBMgc39kaivKt3Nft7efcrS8dgxM6UpgHeRykj3a347wSgSoY6S1WqyL U9Ja6FsLb0E

FIND.
(a) 3A + 2B
Solution
3A = 3TuWBFJ6nEtKFYElUvK YG82cTpE1TfhNs48OOH3SBgh5q9cZuHh ArLI2U3h7TLMekmOI3LK Jux6IuZ0dw1NNZ9B2WiUjWWNnIT6R9iz4JWjSGEb3vA3CFYELl2FZVs0UGtXTg
3A = DrtRRFNeqCqdzowKFIUswTB MTQJCJvqs3 RbdyNCal3ipivb2pC9URUof LtVR0WwaNI54UOWVD71T2qvIIOj9yRHnUqeysIhe1w5Cfh8ozPZ8n5ASmBLWFv8Ad7fmzCSUm AU
2B = 2 JV5OIix60Ws 9hiotJ4UJ2JFBbfRbQqIZwf5LeF5MgUYpbgg0H HXwCzktf5tyTUh8Irqtu9 RjSRhHhg5FeAXP8ag5egwpGUpyy2uxbY74ji4U XOjl8 AM0yWuG 12aH6 AZI
2B = J039NAUKxja2b38zHLj2dis VKL4XH V5kuYgWfU4UmbCBaYs6ai ZAsL5atA86n2hd0jGPJg644P5poYAN7RzwqTqDqPgp FO2JBe5LLegisBHGcqVROU7m47FzKf19iVpZbxU
3A+ 2B = Svb6gDsXVA9DSX1j9jkJKWcLGRbBQnuWkmBb IueLCbD7Y8ShkZM7kkmIm1xrKDAfC5JR6d61U6 Syvuv61cOhx WZ0ZnAtCrUa0oND5O7RbXuaeWMK2AKzd4Jh L4RfDr8wk
= 4YvU3l6jt7TsEAMhMQa9oV5DZGYL Dd WhXfcYPopb7XpLCoIG4JzZT72vIm2F57TqzMAtpY7Z0M4wTVt119ANr7xjZTA5I4ySqKsQVF0Q1Ygj5ChxcksGDNPh7s0Ncc0Y5CkgU



(b) 5 ( A + B)
A+ B = YqO 5dwkW2R4BlUFlmt7SMRAfJm1dPUlvQaiEZhGGEkcPmyL3RfGk MTQBDmXBO7bbkX4kHi Osr9rqUktpd7KfPwcGr3TeQmVIHGz8qnlCw2r NHGL 8CjPjDZBZkY8kZLLBQ= DAlqEl5l0Mw6gRfnm5KsRB6MmjXXOy2rvr5wBI1EZgJ2DKFy4ey18xjlRkmw3B8MZd2ZUm9MUt9StgKeRUwoawgTq I2y8xHnfCGaabiXw2Kn AMen5FNAGKIo9Bw8Y7iN6wJbI
5(A+B) = 5Jj3m6rvWV0AEVAM3awLT COLtk5SqGLVxrxsaVqYl2 JkPQd2kSMwceJGVz XzM89Y RnwgZfFyEu Ublek7IvQzX7XPx Zsg8p4mj2ejW4jq9Zl XAq3myUn9G9 D8l O3V BM
= D0su1BAwyguWq0YMgagnztRnijNMjh5Kn4Ro VaBmbxFA25voAUR69LIIblqboSrSPdKICgrEwm6WBKVAwJFSnOjoTxOe0raMyNSb0m 2nyvsFk49djPOoyky6BvOOXjoOKLCNU


2. Using the matrices;
A = 6Fe9kGzjkOs9YS45sojEGHOiAt2cGIjd N 4En3naZPaNfsZXNTgcIsDzIfLZstOpiSXJo11PEJMbTbT0FXDpjr OAeFeXqfXkD DB 1JMsf5vr Jb0x EniUIN5tu4dkioFlPM, B = 4PpXZqwdzfpnHaGIHCffWs0eUuRfc71UaHIoXiDMaMKIUg8ApsbYMtrpMobQDi0vS HI9HD6GHniKYuspG35vEUSmj3x2x31noLfCgZY1xH4QAz8Xrp96tB5e5T12ck7hD4x Mc and C = S3vvpWQ5IlZkxQs2diKyjfaR 5 InAQaJbEaEPZ50iFy1UB3YSDetgMJOcmQkwJBPZXAKl GBSFB2yuLlQ6gYUHjUMLhEVcS3lFnfoc4MUHJXA5LNuu1pirr1FbonGh9vBMbEMQ

a) Find A (BC)
BC = 43TOMzKYrAVjjxKvoL BNoC9co2crL8ki5gA P BZeapXb6 BSMJn8wOcDivX3VROmdApkNWx2wjZTng4Rr68CGKB19WK3N4VQfUpbSrpha1gZLuXgnZWMh8jiZHKTYtXfXYAck
BC = Npc3Gzzx7iQgmOgIxDwFwekLhqdpHRZaPBmWqQncVfizpXakKHD16Q G7XfbYIOWr4GJnXlSKtuNMukYgwroQEPkhlRGEdcatWUVydK63CHeVKO0TFXL5Q2OaMPvQAqEm4ykI50

A (BC) = NmPa2DJpcay8r8Ufg6UwtkAJ3RQX UagW SCAc69a5 TO5POCz6 QY1ZsQi0CF7FHq28PtmbyYC4OJTsy8fHLAUsEklVXqrRqv0ALpZzvCs 1CioP8Dg1bNzrj0 4VBvutzgKew Npc3Gzzx7iQgmOgIxDwFwekLhqdpHRZaPBmWqQncVfizpXakKHD16Q G7XfbYIOWr4GJnXlSKtuNMukYgwroQEPkhlRGEdcatWUVydK63CHeVKO0TFXL5Q2OaMPvQAqEm4ykI50
= GWzjjHw0tB3i8Xb7iQs99P XsaRLxuB3n8XBSuoPWQaANpA9vV197RAozq3rVVfIBCDDn CknLGkuwMZn MX3Nturf0O5wz394PZMcxS BIzVx8guMeZ OPMLPk9GcPQtVj7pJQ
=  A3myd30wm6WtypXiDogw1Ikv1yxyisnzST3WidU EGwFH2xnC7zkBG3iQ WAr FuaOeTSFtYEk5R DRhTTY9U2baa1WjMTGORFNpxqugtVypZ9FvMsH4OGDMz1lRLuFN8xYVGw


b) (AB ) C
AB = 1vE55Oj4XOsWMIBEmBN FctW XSKJZV LnfRmhfxcSoOEcs5SeSlDyvmQGk9Ez0EbEx8D8qDsg4UIvtawjwtKKxNWm8B4mYWUYKeNaYWZ62 YXG0aFSe Bi U4UaBfvQ3fY8 H8
AB = OeIrVaEYK8vq176VEbmOnrxsYd7tHFrv FscSOQ2JdJ0TrPzhdPQVJol6t7W47lAu51 E6kbCvP PyCLGzS88ekG6dNgW5F9rsfkedF7hrSIWgJOIl39NVJk1b Tg R MFsjwDE
C = Ixyk 8eHc9Uzs0hcpvMkQNJTQPpvTeYNBA9stQH6kv0tf9Wr93psNQ2IPY6ilmdomE8QqY DFpD7G2ATHJ52R6lDrBYwhEKE9R1CqCB L3mAN9aeA EW9Teka26oCWFC9GqrCKE

(AB)C = Wju3id08 P D MA OiW2v LUm1Kt5ewXPEYFwYiqSnfgcxUpTrWeEg86a1TLuFTINsZVyb1 8 6YCY0Y OcE5zZ83tjZ1M7JJ5d6S7TVGtnpUfI29TOsgbtYV28C54E5Yj3XBMs
(AB)C = RZ7GRw8bCMW AsHdQLq2 UHXo9pizZoGMs4D8F59lDIbPQ0HTiiqgXypqOCRXQgHhWUj6nhYg3LVqjb1 ObdbEktko OnjGD5q21nhUm25SVhzNPKvf3J1qNHB1S6GJcd99wOL8


DETERMINANT OF A MATRIX

BIjg1rrJnW6K0hvuQFzq9N9honqs6zPmu3yOsp44C5zNSbnYZ830d WoSCZK1MrrgOdsG HoOlQJH KmtelaWI7fzeSi1wu8Q8RBntGBbm 0ZhYszzX EalFeGn31a6T24q1Ag
NOTE
Determinants exist for square materials only.

Calculate the determinant of a matrix and tell whether the matrix is singular or non singular.
1. A = JbAsjM7rINLdzqMQInnBxP3 5s93oDsiE6OYLnvM0oicB74zwGn5OXqei DL0H87AyD39xUHIZs S3DI2iCZ0A7DFUJxIdHF6bnMrxnqVE Am3OO5LkhDbE1jrhSZnoZHv8rTC8

Solution

BY4s6KpBH6OOWnqUnXh0FKOidBHxGs8FUJ07lVQIDrgyvAHCDepAf8ytehPnSHXhcuQkw2a1XM8oj9mh YssqgRDWKMMbJ70gDk0ol8qElKfkVQQsm9P4SW33PYoxeDXnvMxv5M= (-1 x4) – (2×3)
= -4 -6
= -10
A is non singular matrix.

Inverse of matrices

The inverse of a matrix say P is another matrix denoted by P-1

A3SzqwnHJEFyT5NdhRyqU5O7ACbB37yjCPpUjmmLR2Il7w7X7IpoTYvubqI8SaZCX8Oqe8HiBOJbCxXhv7yzpiQvj ZwAJxD4ZvRR3B6aSQb Mgfd3xxrD6pmYWvrW3T3ZskZZE

Nu05N3e7e4igED2AFEkyIE9G7ijcDJnk3OlZyoSKpuZLSckZf4C VS46XdCHjzNV2wgsWCzwqITtL0UUZMwonKbkWwO7VFcILLTxIAi2Riprmp08BK4hkVJI1cEJmXuEvSKzjCg
Nu05N3e7e4igED2AFEkyIE9G7ijcDJnk3OlZyoSKpuZLSckZf4C VS46XdCHjzNV2wgsWCzwqITtL0UUZMwonKbkWwO7VFcILLTxIAi2Riprmp08BK4hkVJI1cEJmXuEvSKzjCg

MI6bsjStjXY BU0hdQvAP4xcgG4ryNamsxnpp N6gFudJuVwqXC3myh3gX1sNjb YqODiBeRXPyCbjrOB7n10geUlDjQiIGZlCn1Xe1xwgA BwvBslOnMjiYkDw0wJb4eW5Y2zQ


NOTE
CoACVauiza1wewx7SN80I06kIN00MNqImvTUIKp6wnEog0pfRgLf99Sv6FwkHRDDJZSRAdMrdt87L Tol A9B7yKF2W30RHh WvF5yeHd5jRNGd7ZkkuPzqjR7pB07xm WFoZN4

Can be found by interchanging the elements of the leading diagonal so that d takes place of a and a takes place of d. Change the sign of the elements in the main diagonal so that b and c becomes –b and –c respectively.
Divide each element by the determinant of A
2. Inverse exist for non singular matrix.
3. Singular matrix has no inverse because they have zero determinant.


Example
Determine the inverse of the gives matrix and indicate if it is singular or non singular.
1. A = NzZE6Ialw4Opbxd EKCzpRVTvmQeua01ZFxC6HW0aDNfCTDf3o7p VXvQ44QUh73G7TodLzmXtMrjCPV0TB IKGGdtG 1kYRjgloUtgBw5osoQdmlBwichI9L8emeMBCIOWt6Yk

Solution

Determinant; (A) = (4×4) – (-4×4)
= 16+16
= 32
A-1 = 1CAx2AT4OVxghyVW7oWjFkRTftqGvqtvx7G9pkJJM3yXYsorVDSA 1FbXXcxKRYYOblX9ZLX MDgxoNKnF28hXIbSfz77g3U8CM HOReoHL L0KUxa6ugqeUzyjsi7vXnuAnviM PONzcIbtee MopC8i9xs 4zVGND7t0w1a4ihs4GwwXywdD WSwfD5ihpLHyjNnMGFqIrOjPcCfJ3GFt3Wnw4puZS9GGX IILnuFA6nWjyJ XuWsjusQifHMbZdNYAEnKUJHRGuE
A-1 = 7lLnkXkSlp66yu46sSv61yfdc SoQU5Ihdje3ft2GAlEdW L7gDZY15vDOxN2EF8EkzbWWCQwKL LUa SX ZH2 GLXUXUrW76fDP34blyJfOSjZLx4WI5yKjoikhtLz2oq3kqU

A is non singular matrix.

2. B = SNKna7oM9P VKSJax8FnUs1iotWt28RjheVXFjlfmGP8nK PTP Lan1QaSxMvTE4MGPv0eQSGAAxPUM4rPzWh6QdZZwL BpUjGk1l60lCedW0whpJKyEfYtXuSKAg2zkN6uUrzw

Solution
Determinant ( B ) = (-1×1) – (-1x-1)
= -1-1
= -2
B -1 = -1/2 STpGwfLUv7k90RvvZtl2JSC R11rMLL3EH3LtUOalIwiReJYBFbbxBQ5cDSRdCCMT4viaGplR6u5BqC0A0T6 Krm5mBLcao5WHnijFtY3m2GNXYpH1tDMB Te9GkyYEooUZorQc
B-1 = H0 BiinjKcScezPJJtktmQHbTuXm0mNN4Zj7OnNdoeUOHl MpzRFuwW4KU6Z0WoYXKA9uYxIHWG3WVve2iiDCBHbxOfUTmIZV6eSQ0haKjWWUQba8k DePIErjR9MiPE2 PCi4



MATRICES ON SOLVING SIMULTANEOUS EQUATIONS
Questions


1.5X + 6Y = 1
7X + 8Y = 15
WcLwtCQLNF R9oMUZlJwlyaiTdOBkyWtQ7GD4D7tYj5X3ljZig1VH BLfPmygf94zHPB4Znh Q4Jj GfSLWOylqB26K8R8mMeFAstE5iSFFeiCwu2SxTmn653RVvczUkvFshTw4 ZUv76UtT78j8d5Gv6raDqfE2lAaBm4sqqNunFlhp2v5ICcXFTrGeW2XMeE1gfl5H23BZqDouUlU1NzQedmO5RDl UtFaD8ykU08o1GGlGq 5tWGaFB7L ZGXy2iKMSNX7gjlxPY = B9JPddpfBrti3 OmcSNTdvmhW8V44B7H4rlcQR MJmZOA2wNDH6KcMcMMGpe 8F55SoTqhedpuwqeDP2fLPIFrcqtGf23FWBSf1TuCMjN MJQEvsTy9Yw1V KKyrUnNPeEs4cts

Let
WcLwtCQLNF R9oMUZlJwlyaiTdOBkyWtQ7GD4D7tYj5X3ljZig1VH BLfPmygf94zHPB4Znh Q4Jj GfSLWOylqB26K8R8mMeFAstE5iSFFeiCwu2SxTmn653RVvczUkvFshTw4 be A

347DH6qFebskfrAW2QH56xkbFEpoEqzKtSC2LPbFAPKrjFTI804UItgr1POoKdSKoCZU832JP1UklODtt0MsQyaj58seQKdeXn5w0yUll6FGT0Y4A8F5yiBomlI3a3Za5Jzv E0= (5×8) – (7×6)
= 40 – 42
= -2
A-1= L Rx7V GsakLHHWU0HqT6gGCRQhE3jiciaU0DS5jHIZjaQfbqmIClilviZPHYUFVicugznoOVqUmnUHjCY1JhG Sv65za81ZhnNFNv7OREeucz4MTAVP Z0SWNlATkkjOBi1Aec
A-1 = Kxodz3Xr2EiMeWhM9wDaj2qSpjc5eOPl3P OUCjkNZG3CBeNbiHUVTVlU1jGcWNB JyURFydE9VG9GQfMEbJ Zn9zTMcwyJq3RxQcTAFHIR7PleO6UIvhNNKCvQ2atXKZAa3vFQ
= 6Ae5Qw YndefT1yGPttveHvY54fRJBPmC KEY6juQIUh03aLMTBWQj9uUvt4gvnnHHkERvR0lqOWVNq0dB59 PSy BKcwV6fWYGS0gdsE22 Rcaxwy0fdpgNfEiX OzqluIYPw ZUv76UtT78j8d5Gv6raDqfE2lAaBm4sqqNunFlhp2v5ICcXFTrGeW2XMeE1gfl5H23BZqDouUlU1NzQedmO5RDl UtFaD8ykU08o1GGlGq 5tWGaFB7L ZGXy2iKMSNX7gjlxPY = Kxodz3Xr2EiMeWhM9wDaj2qSpjc5eOPl3P OUCjkNZG3CBeNbiHUVTVlU1jGcWNB JyURFydE9VG9GQfMEbJ Zn9zTMcwyJq3RxQcTAFHIR7PleO6UIvhNNKCvQ2atXKZAa3vFQ
= RMjE CwbbLdjS6uXnyw7PPfyQYjagYQK ENGwKuYwnG1i9gvEHu GPaATAfSptqei5i7uVTvmLq7af GhGSPCB0IOTgzjSTjpnKwJP7RlZ2lMzKk3OWNqe2MUATZWWkQUFyPJHc = 8DNVgxxkLtqs Y2YsJ U4OJwSv5mTG2JzAqcOgHRx Jcn3djlBZGzj23E29 YGRgYFP8Z0ez99jPiD7ejcE12nx8j0iRvufZa8VHXpVvcpoGgWP UP6M7Sykn B5I0a3vY8lb9c

TKHt FiVT7wEGiuAKlixKPZxjAmhlDoUrBcyN34w PswSIuu 8Ys4bEFP3zGlMPz WG3UnyFD 5Cv30a2Wutbsl0HFTVwjcSy6NxhQVBITKZz1mFrazKhQGvMCvG0S0oo 94ixU ZUv76UtT78j8d5Gv6raDqfE2lAaBm4sqqNunFlhp2v5ICcXFTrGeW2XMeE1gfl5H23BZqDouUlU1NzQedmO5RDl UtFaD8ykU08o1GGlGq 5tWGaFB7L ZGXy2iKMSNX7gjlxPY = OI8b5Y7KAm7qHpTevH4cIvVm RuwbVizt2QJQgrWcIxmTi E2Kl GASjjUoZj50X3URsl7Iy T40U4UvF4k3Bj B IVweaikE7WzsR2f4BIV79BRldqr95TnB2031mGodWLWwzo


x = 1
y = 1

2.Solve the following simultaneous equation by matrix.

4X + 2Y= 40
X + 3Y = 35
OTpuTHM27Q5Nni8uHSGDrwEmlwEPKa0S8pnORy470egWfIvrxodTNHnAAqUTIUdMy3oqi RbRDPDRBFUAuLUMTCJSEQvDfXImZkE NQnEu0nYAmASyGaCZvOazBpBW4VE09nbg ZUv76UtT78j8d5Gv6raDqfE2lAaBm4sqqNunFlhp2v5ICcXFTrGeW2XMeE1gfl5H23BZqDouUlU1NzQedmO5RDl UtFaD8ykU08o1GGlGq 5tWGaFB7L ZGXy2iKMSNX7gjlxPY = UIY2 XRNsk4VY0E5Xt IOZ7MGP7QKGTyLnPof9CcYTh J7QN62cSaILsbgR YXk Y C MFqGVnLAoNhJGXLJUDdUt7GNLIo9GEocOcRLKYTCkjgGdkJNlhIC0wf 2ZVKic6DE
Let OTpuTHM27Q5Nni8uHSGDrwEmlwEPKa0S8pnORy470egWfIvrxodTNHnAAqUTIUdMy3oqi RbRDPDRBFUAuLUMTCJSEQvDfXImZkE NQnEu0nYAmASyGaCZvOazBpBW4VE09nbg be B
IZR6ULzJ8PtBRPuW16e2iGi PbkHlFKfHeAc7N3CzHQYE0GrOHGp2VCxPAsNhQTTn1dbZe5p UPvDuqmVb2ZIty7UcCZ4lmtHdm4GORdYX4UjY FmcUYLZFLe15Pdv H7z9QAKQ = (4×3 ) – ( 2×1)
= 12 GOF2bTfKfIfeU0L8uvpCxRfG5BzpbnkDO0AY5xzlCq4ZXf3TAsJkuapWhfwj4SbzZjf84NyAtcxYhclmPdpvopBf6x C7Ip0afEwjEIKEfqDPO 913HtvYJO2qDYYdL48 MfjwU 2
= 10
B-1= WzgLbyosd X1SWohMHj8wzayOFZbClynaXgK Li5MMK58x6Zmeg9poEtVdx GscUCZEgQUO9n KXlDuLLmhlLCKGqRjC809KpTKcqCN VxbKvFeYHuatbXT7cSQa9aCokzlSWhc
= Gish2LLDQiS7uy8Q HU1 G9qU1WCK81ihkuJOcgC8qxJIimKf9ipcbDrdXbNX0nMn8qG UbPzeSYMO2gIk5Lr0BY9EyyWb8VSlXGcZWs0PpLCQ8hLFvmzvL VzlBnQj6NXR711k

E48VY7IB2tlRSlytyNjn7p8fvxWMIqBevrk14nTMdT6dmS5vyBwBL4Jxugg7 WACt96Po W2JpuwTv5rSXCdelybLALVPe0LeHUjwLDWYR 8UGvKoYnJetS9dAl76SfTw9dVw0oZUv76UtT78j8d5Gv6raDqfE2lAaBm4sqqNunFlhp2v5ICcXFTrGeW2XMeE1gfl5H23BZqDouUlU1NzQedmO5RDl UtFaD8ykU08o1GGlGq 5tWGaFB7L ZGXy2iKMSNX7gjlxPY= Gish2LLDQiS7uy8Q HU1 G9qU1WCK81ihkuJOcgC8qxJIimKf9ipcbDrdXbNX0nMn8qG UbPzeSYMO2gIk5Lr0BY9EyyWb8VSlXGcZWs0PpLCQ8hLFvmzvL VzlBnQj6NXR711k

TKHt FiVT7wEGiuAKlixKPZxjAmhlDoUrBcyN34w PswSIuu 8Ys4bEFP3zGlMPz WG3UnyFD 5Cv30a2Wutbsl0HFTVwjcSy6NxhQVBITKZz1mFrazKhQGvMCvG0S0oo 94ixU