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Equations of straight lines Questions
1. If the equation, where R and V are variables, is rearranged in form , determine the gradient and the yintercept of the line drawn. (3 mks)
2. A straight line passes through A(2,1) and B(2,k). The line is perpendicular to a line 3y + 2x = 5. Determine the value of k. (3mks)
3. A line whose gradient is positive is drawn on the Cartesian plane and its equation is. Calculate the angle formed between the line and X axis. (3mks)
4. A straight line L_{1 }passes through P(2,1) and is perpendicular to straight line L_{2}, whose equation is 2y – x + 4 = 0. Find the equation of L_{1}. (3 marks)
5. Find the equation of a line passing through point (3, 5) and perpendicular to the line 2y + x – 3 = 0, answer in the form of ay + bx + c = 0 (3mks)
6. A straight line through the points A(2,1) and B(4,m) is perpendicular to the line whose equation is 3y = 5 – 2x. Determine the value of m and the equation of line AB (4mks)
7. The straight line passing through the point (3,4) is perpendicular to the line whose equation is 2y+3x=1 and intersect the xaxis and yaxis at points P and Q respectively. Find the length of PQ. (4mks)
8. The gradient of a line L through points A(2x,4) and B(1,x) is ^{1}/_{7}. Find the equation of a line perpendicular to L through B. (3 marks)
9. A triangle has vertices A(2,5), B(1,2) and C(5,1). Determine:
(i) The equation of line BC. (2mks)
(ii) The equation of the perpendicular from A to BC. (1mk)
10. The line y = 3x + 3 meets the line L_{1} at the point (2, 9) and at a right angle.
(a) Find the points at which the two lines intersect with the x – axis. (3mks)
(b) Hence calculate the area bound by the two lines and the x – axis. (1mk)
11. A line with gradient 3 passes through the points (3, k) and (k, 8). Find the value of K and hence express the equation in the form ax + by = c where a, b and c are constants. (4 mks)
12. The straight line through the points D (6,3) and E (3, 2) meets the y – axis at point F. Find the coordinates of F (3 mks)
13. Find the obtuse angle the line y – 2x = 7 makes with the x – axis (2 mks)
14. The figure below shows a sketch a of a line 5y3x = 15
y
Ø
X
Find the value of Ø (3 marks)
15. A solid right pyramid has a rectangular base 10cm by 8cm and slanting edge 16cm.
calculate:
(a) The vertical height
(b) The total surface area
(c) The volume of the pyramid
16. The line passing through the points A (1, 3K) and B (K, 3) is parallel to the line whose
equation is 2y + 3x = 9. Write down the coordinates of A and B
17. Find the value of a if the gradient of the graphs of the function y = x^{2} – x^{3 }and y = x – ax
are equal at x = ^{1}/_{3}
18. Two perpendicular lines meet at the point (4,5). If one of the lines passes through
the point (2,1), determine the equation of the second line in the form ax + by + c =0.
19. Find the equation of the line passing through (5, 2) and with Xintercept as 3. Leave your answer
in the form of Y = mX + C
20. (a) copy and complete the table below:
x  0  1  2  3  4  5  6 
y = 2x – 4  
y = 12 – 2x 
(b) (i) On the grid provided and using the same axes, draw the lines y = 2x + 4 and y = 12 – 2x
(ii) Hence use your graphs to solve the simultaneous equations
½ x – ¼ y = 1
x + ½ y = 6
(c) By use of substitution method, solve the simultaneous equations;
6x + 4y = 36
x + 3y = 13
21. Find the equation of a line through point 2, 4 which is parallel to 3y = 2x + 8.
Express your answer in the form y = mx + c.
22. Determine the equation of a line passing through (1, 3) and parallel to the line whose
equation is 3x 5y = 10
23. On a certain map, a road 20km long is represented by a line 4cm long. Calculate the area
of a rectangular plot represented by dimensions 2.4cm by 1.5cm on this map – leaving
your answer in hectares
24. A straight line passing through point (3,4) is perpendicular to the line whose equation is
2y5x=11 and intersects the xaxis and yaxis at the points P and Q respectively. Find the
coordinates of P and Q
25. A triangle ABC is formed by the points A(3, 4), B(7, 2) and C(1, 2)
(a) Find the coordinates of the midpoints K of AB and P of AC
(b) Find the equation of the perpendicular bisector of the KP
26. The equation of line L_{1} is ^{3}/_{5}x + 3y = 6. Find the equation of a line L_{2 }passing through
point T (1, 2) and perpendicular to line L_{1}
27. Determine the equation of a line passing through (1, 3) and parallel to the line whose
equation is 3x 5y = 10
28. A straight line through the points A (2, 1) and B (4, m) is perpendicular to the line,
whose equation is 3y = 52x. Determine the value of m
29. Determine the equation of a line which is perpendicular to the line 2x + 3y + 4 = 0
and passes through P(1,1)
30. Koech bought 144 pineapples at shs.100 for every six pineapples. She sold some of them
at shs.72 for every three and the rest at shs.60 for every two. If she made a profit of 40%;
Calculate the number of pineapples sold at 72 for every three
31. Solve the equation x + 2
x – 1 = 5
3 2
Equations of straight lines Answers
1 

B_{1}
B_{1}
B_{1}  
3  
2. 
B1
M1
A1 
Equating to grad  
03  
3. 
M1
M1
A1 
 
03 
1. a) Length of diagonal = √ 10^{2} + 8^{2}
= √164
Vertical height = √16^{2} – (√164)^{2}
2 = 14.66cm
b) Height of the slant surfaces
√16^{2 }– 4^{2 }= √240
√16^{2 }– 5^{2 }= √231
Area of slant surfaces
( ½ x 8 x √240 x 2) = 124.0 cm^{2}
(½ x 10x √231 x 2) = 152.0cm^{2}
Area of the rectangular base= 8 x 10 = 80cm^{2}
Total surface area = 356cm^{2}
c) Volume
= ( ^{1}/_{3} x 80 x 14.66) = 391.0cm^{3}
2. Gradient of line AB = 3 – 3k
K +1
Equation of other line can be written as
Y = –3x + 9
2 2
its gradient = ^{3}/_{2 }
Hence 3 – 3k = –3
K +1 2
66K = 3k 3
3K = 9
K= 3
A(1, 9), B (3,3)
3. M_{1} = 2x – 3×2
M_{2} = 1 – 2ax
M_{1} = M_{2} at x = ^{1}/_{3}
2x – 3x^{2} = 11 – 2ax
^{2}/_{3} – 3 (^{1}/_{3})^{2} = 1 – 2ax^{1}/_{3}
^{2}/_{3} – ^{1}/_{3} = 1 – ^{2}/_{3} a
–^{3}/_{2} = –^{2}/_{3}a
^{9}/_{4} = a
4. M1 = 5 – 1 = 4 = 2
4 – 2 6 3
M2 =^{ 3}/_{2}
i.e. ^{3}/_{2} = y – 5
x – 4
2 (y – 5) = 3 (x – 4)
2y – 10 – 3x + 12
3x + 2y – 22
5. Points (3, 0) and (5, 2)
M = – ¼
y – 0 = – ¼
x – 3
y = – ¼ x + ¾
7. Grad = 2
3
y – 4 = 2
x + 2 3
y = 2x + 16
3 3
5y = 3x – 10
y = 3 x – 2
5
Gradient = – 5
3
5 = y – 3
x + 1
3y – 9 = 5x – 5
8. 3y – 5x = 4 0r equivalence
9. L.S.F = 4 = 1
2000000 500000
A.S.F = 1
^{2} = 1
5 x 10^{5} 2.5 x 10^{11}
Area of rectangle = (2.4 x 1.5) cm^{2}
= 3.6cm^{2}
Actual area = 3.6 x 2.5 x 10^{11} ha
100 x 10000
= 9 x 10^{5}
= 900,000ha
10. 2y – 5x = 11
Y= ^{5}/_{2} x + ^{11}/_{2}
g = ^{5}/_{2}
^{5}/_{2}m = 1
M= –^{2/}_{5 }
Y – 4 = –^{2}/_{5}
X + 4
5y + 2x = 14
P(x,o)
5 X o + 2x = 14
X = 7
Q(o, y)
5y + 2 X o = 14
Y = 2.8
P (7,0)
Q (0, 2.8)
11. i) K ( 37, 4+2) (2, 3)
2 2
P (3 + 1, 4 – 2) = (2,1)
2 2
ii) K_{1} =3 – 1 = – ½
2 – 2
= 2
12. Gradient of L1 = ^{1}/_{5 }
Gradient of L2 = 5
Y= mx + c
2 = 5 (1) t c
2 = 5tc
C = 7
Epuding L2
Y= 5x + 7
5y = 3x – 10
y = 3 x – 2
5
Gradient = – 5
3
5 = y – 3
x + 1
3y – 9 = 5x – 5
13. 3y – 5x = 4 0r equivalence
14. Gradient = g = m – 1= m – 1
4 – 2 2
3y = 5 – 2x
y = ^{5}/_{3} – ^{2x}/_{3} g_{1} = ^{2}/_{3}
g x g1= m – 1
– 2 = 1
2 3
2(m – 1) = 6
2m + 2 = 6
2m = 8
M = 4
15. L_{1} y = – 2 x – 4
3 3
M_{1} = – 2
3
M_{2} = 3
2
L_{2} y = 3 x + c x = 1, y = 1
2
1 = 3 + c
2
c = – ½
L_{2} y = 3 x – 1
2 2
16. BP = shs. 144 x 100
6
SP = shs. 140 x 144 x 100
100 6
Let pineapples sold at shs. 72 for every shs. 3 be x
∴ At shs. 60 for every 2 will be 144 – x
x x 72 + 144 – x = 3360
3 3
24x + 30 (144 – x) = 3360
6x = 960
x = 60
17. x + 2 – x – 1 = 5
3 2 1
2(x + 2) – 3(x – 1) = 30
22x + 4 – 3x + 3 = 30
x + 7 = 30
x = 23
x = 23